18436
18. A stone is thrown with an upward velocity of 45 m/s from a building 30 meters high.
Find its height above the ground t seconds later if height can be modeled by
h(t)=-4.9t²+vt+h, where v
30
=
the initial velocity (m/s) and h₁ = initial height (meters).
When does the stone reach the same height that it was thrown?
h = -49++Vot+h
4.9t
45
t
30-4at 45++30
0= -4.9€²+45+
Hat 45
ta.1837
Hat² = 45t
When will the stone reach its highest elevation?
2
h-Hat +45t +30
9,18 sec
