求解第九題🫰🏻

點:ToA:Top=2:1((E) 滲透壓:TA:p=2: Um = WA B:2210 MB: Ab AE 有下列(a)蔗糖、(b)氯化鐵(Ⅲ)、(c)硝酸銀,水溶液各0.1Mㄨ任取二種同體積混合。申: (a)+(b),乙: (a)+x (c),丙:(b) + (C),則下列敘述哪些正確? (A)沸點:甲>丙>乙(B)凝固點:甲>乙丙(C)蒸氣壓:乙>甲>丙(D)滲透壓:丙>乙>甲(E)滲透壓:甲 >丙>乙。 北端頭 AAA

22題的選項要怎麼改？為什麼要選D？

Miss Ghost Month.os or to gribnazob 2'slqosq dauortiAailed ecause of grows modaros (A)What lean bas dot (B)Itque a bonisme (C)Which Id" aniye (D)AS vo wors and amsidorq 21. (C) You can learn a cake by reading the recipe.add()()(A)(1). (A)how is made (B)which to make (C)how to make teen (D)what you 1) B make() For such a shy person as Stella, (at a gathering always gives her a hard time. (A) () (E) (A)when to say it (B)how to say it (C) who to say itsmine (D)what to say ()()(A) people 23. (B) The typhoon is coming. It doesn't of (a good idea to set out for hiking these days. A) (A) (2) 小 (Alseem thated (B)seem like a sho(C)feel siq diod ano(D)looks amotau E

22題的選項要怎麼改？為什麼要選D？

Miss Ghost Month.os or to gribnazob 2'slqosq dauortiAailed ecause of grows modaros (A)What lean bas dot (B)Itque a bonisme (C)Which Id" aniye (D)AS vo wors and amsidorq 21. (C) You can learn a cake by reading the recipe.add()()(A)(1). (A)how is made (B)which to make (C)how to make teen (D)what you 1) B make() For such a shy person as Stella, (at a gathering always gives her a hard time. (A) () (E) (A)when to say it (B)how to say it (C) who to say itsmine (D)what to say ()()(A) people 23. (B) The typhoon is coming. It doesn't of (a good idea to set out for hiking these days. A) (A) (2) 小 (Alseem thated (B)seem like a sho(C)feel siq diod ano(D)looks amotau E

求解🙏🏻🙏🏻🙏🏻

1) 行政院通過《社會救助法》部分條文修正草案,新增實物給付服務專章,明定 未來地方政府可視需要及財力,自行運用民間資源,以實物給付辦理社會救助 事項。各縣市也得因地制宜,採行實物倉儲、實物券、資源媒合或物資輸送平 臺等方式,推動實物給付服務。請問通過此修正草案的目的應為何? (A) 放寬貧窮線,將中低收入戶納入救助的對象 (B) 照顧因天災而導致生活陷入困境的弱勢家庭 宝 (A) 日用 TOH 理 (C) 廢除現金給付,提供弱勢家庭實際所需的服務與文物纯由) (D) 活絡社會資源,擴大社會安全制度照顧層面,香港農 10卅幻必 6 海山高中

Feasible ways include keeping interest in what we learn ,and excluding anything made us distracted from works. 請問上面這樣寫文法有錯嗎～ 另一個版本是有在mad... 繼續閱讀

想請問第16格 詳解說是倒裝，請問倒裝句要怎麼分辨，然後為什麼這邊的倒裝要加as （ 我文法很弱 非常感謝解答😭❤️😖）

第16.至20.題為題組 The origin of the well-loved stuffed toy teddy bear can be traced back to the story of Theodore Roosevelt, the president of the US from 1901 to 1909. In 1902, as a devoted hunter, Theodore Roosevelt 16. he loved hunting, he failed to went on a trip of bear hunting with his assistant and staff. Much find a single prey that day. One of Roosevelt's assistants tied a baby bear to a willow tree and suggested that he shoot it. Roosevelt refused and thought that it was cruel to shoot a defenseless animal. Little 17. the president know that his actions would cause the creation of a world-famous toy. The story soon spread to every corner in the country. Newspapers around the country kept recounting the story of Theodore Roosevelt and the bear. An owner of a sweet shop heard the story and was deeply impressed by Roosevelt's 18. . In order to express his admiration for the president, he had an idea of creating a toy bear 19. Theodore Roosevelt, or Teddy. These stuffed toys, now known as teddy bears, sold like hot cakes. Women and children alike carried a teddy bear with them no matter where they went. Interestingly, Theodore Roosevelt himself, while 20. for his second term in office in 1904, also used the teddy bear as his mascot. Nowadays, the teddy bear remains one of the most popular gifts all over the world.

請問這題正六邊形面積式子怎麼來的

*J (3976) ( +1²) = (a+b)". 18x32 (a+b)² 數學A考科 > 0<a+b≤2+6=" 9 zab3 ab=2 TO 5 2uth, 397b 2345 ab33√3 9.93 30+5=18 atb 1953 = "2 30²= b² Ab=53a α=53,6=3 2 P2ab請記得在答題卷簽名欄位以正楷簽全名 10. 如右圖,六角柱 ABCDEFGHIJKL 之上底面ABCDEF與下底面 GHIJKL 為兩個全等的正六邊形,側面為六片全等的矩形,且上、下底面的正六邊 Ap 5 形與側面矩形皆垂直。設AB=a, AG=b, AI=32,請選出正確的選 項。 30+ $827-18 1 341 (1)3a²+b=18 (2)矩形 ABHG 的面積有最大值為3-03 CAB ab=356號 3矩形ABHG的面積有最大值時,六角柱 ABCDEF-GHIJKL 的體積為27~3 +za+bb = 2x256=456 (4)矩形 ABHG的周長有最大值為2~62(a+b)+ 512G+b) (5)矩形ABHG的周長有最大值時,六角柱 ABCDEFGHIJKL的表面積為 19x9x+axa h (3,1) 第 4 第共 頁頁 7 F E D \B L 32 a H a I 9√√3+54 2 a+- 202 -=20 x² = 30

求解DE🙏🏻

(BIC 設 deg f(x)≥4,若f(x)除以(x-1)餘式為3x+2,除以(x+2)餘式為5x-3,請選出正確的選項。 D (A)x-1除f(x) 餘式為5 (C)(x-1)(x+2)除f(x)餘式為6x-1 4-5-6 (B)x+2除f(x)餘式為-13 (x-174(x+2)+0xbxte a+b+c=5, 42-2b+c=13 (D)(x-1)2(x+2)除f(x) 餘式為-x2+5x+130-35--18. (E) (x-1)² (x+2)² f(x) (x²+5x+1 = (x-179 +3x+2 +11x=5 = (x-1)x+2) of torty f(x)= 5-2015=13 4654 +(x+2)+5x-3 11-27--13 +-513 3α=18 ☆02. 已知a、b、c均為實數,若二次函數f(x)=ax²+bx+c滿足f(7)=f(-7)、f(3)<0、f(5)>0,請選出正確的

求解 41題E為何對

300 60 +60 51m ↓ wkw/hr bo kw 40. ~42. 題為題組 5 bob 360 360=6 Flomin 沁 西元前3世紀時,埃拉托斯特尼擔任亞力山 1360x60 360x 70 x 5=300 To w/miAA hr' kw 卓圖書館的館長。某天他在埃及南部的塞伊 度电 亞力山卓 8.00km. 阿斯旺 [Syene,現今稱為阿斯旺(Aswan),如圖16〕, 注意到夏至中午陽光直射當地一口井時,沒有任 何陰影,說明太陽位於頭頂;同時夏至中午在位 埃及北部的亞力山卓(Alexandria),由垂直地 面桿投射出的陰影,計算出此地的太陽位於與垂 直線偏向 7°12'。埃拉托斯特尼得知阿斯旺與亞力 山卓兩地相距 800公里,就能計算出地球的大小。(註:1°=60',1'稱為1弧分或1角分) 深井 12 12 圖 16 27R= F 7 505 40. 依據題幹敘述,太陽位於與垂直線偏向7°12'相當於360°的多少比例,以及地球半徑約 多少公里?(應選2項) 2xRx50 = 800 36 5. 4020000 1 (A) 7°12'是360°的 R=800x50 Ms 1 36 3600 5 (B) 7°12'是360°的 50 30 元 40 50 1 26400 (C)7°12'是360°的 地球半徑約為6400 公里 YO = Su -50 100.11 (E)地球半徑約為7200公里 41. 依據題幹敘述,下列有關埃拉托斯特尼的觀察與基本假設,哪些正確?(應選3項) (A)亞力山卓應位於北回歸線上 B LE ← (B)阿斯旺應位於北回歸線上 (C)埃拉托斯特尼假設太陽位於無窮遠處,即陽光照射在阿斯旺及亞力山卓為平行光 ( 埃拉托斯特尼尚未考慮陽光通過大氣層產生明顯的折射現象,所以此測量有巨大誤 (E)埃拉托斯特假設亞力山卓在阿斯旺的正北方夏至中午陽光直射(或近乎直射) ㄇ射角乎O

想問第十題的選項2是黃色的紙那樣算嗎？

* 35 數學B考科 請記得在答題卷簽名欄位以正楷簽全名 z 10.設P(a,b)為兩函數y=logx和y=sinx 在 為實數,請選出正確的選項。 (10<a+b<3<a<l, o<b<l (2)(bar)為函數y= (3) aπ 振=1 第 4 共7 頁 頁頁 [02]內之交點,其中為圓周率,a、b (2)b=logan P (ar, b) 0.301 0.301 10 圖形上一點 -b 為函數y=log x 圖形上一點 2 元 3,14 y=10gx For (4)(z,b)為函數y=sinx以原點為中心水平伸縮a倍後圖形上一點 (5)(an,b)為函數y=sinx 向左平移單位後圖形上一點 (11. 筊是利用兩個半月形的木頭筊杯,透過將筊杯 預測事情。根據筊杯的正反可分成以下三種狀況 二種為兩正面,又名「笑杯」、第三種為兩反面 出聖杯表「成功」,無杯表「失敗」就不再擲 或「失敗」才停止。若每一個筊杯正、反面出現 "ar = (1/1) b logar = log + = b to 頁