G小題錯在哪⋯

Au equation of state relates the state v (g) True false The internal energy of an animal cell (system) can only be changed by the flow of heat (9) or work (w) across the boundary between the system and surroundings. (4 points). s'open system m True false: Find the incorrect conclusions from the following sentences and correct them. (20 points).

為什麼是28-8

o 4音父 - →f= f 号-1= 40(cm)=0.4(m)。 - G=Lzai= a X5=1.25(m) ºn 4 4 5. 1)相鄰兩個共鳴位置的距離差為半波長 a = 28-8= == 2 (2)y=ar=0.4X850=340(m/s)。 (3)設溫度為t=340=331+0.6t =t=15(°C) • 800 () -基礎大考試題 1.(1) 300 ; (2)0.85 2. 3 3.(E) 4.(D) 5 IT | B音叉 O B

怎麼寫⋯

2.2 A batch of 100g of Na2SO4 is dissolved in 200g of H20 and the solution is cooled until 100g of Na2SO4:10H2O is crystallized out. Please do a DOF analysis and calculate the composition of the remaining solution. (Na2SO4:10 H2O = 322.2, Na2SO4=142.05) Answer: DOF = 0; Na2SO4 28%, H20 72%

第三小題錯在哪裡

3.)* True/false: Find the incorrect conclusions from the following sentences and correct them. (12 points) b H2 •T2 H An ideal gas changes its states isothermally through a chemical reaction. AH is zero because AH is equal to Cp x AT. H TI ® The pressure change does not contribute to the energy state (U or H) of ideal gases. P * Figure 1 is correct for illustrating the enthalpy state of real gases. Fig. 1 AT1 ATL+1a na:daalraa ahonnan kantot fo. U +- IT 1.1 D1

第三題為何是3啊⋯⋯ expansion那內能差不就是小於0嗎，

(3) Pushing the piston down so as to do work on the system 3 PV a (c)Multiple Choice: What is the correct result for reversible isobaric process in which an ideal gas undergoes an expansion form 1 L to 10 L in a closed system? BU-atw DHECPAT (3 points) Pv=nRT AU=croTo (1)w > 0, AU>0,q>0; (2)w >0, AU<0,q<0; (3)w<0,AU>0,q>0; (4)w <0, AU<0,q<0 个小 finat low of thermodynamics takes the

第一題 怎麼想

1.) True/false, multiple choice or short answer. “*” denotes more than one correct answers. (33 points) (a) Multiple Choice: I will have the largest energy transfer as expansion work from an ideal gas system 1o the surroundings if I use a process that is (3 points) (1) Isothermal and quick ;(2) adiabatic and quick ;( 3) isothermal and slow; (4) adiabatic and slow

畫線地方看不太懂 求解說謝謝

INARA WEREW 馬上練習1 如圖所示,有一半徑為R、重為W、材質均匀的光滑輪子,與 高h的階梯接觸,靜置於水平地面上。今在輪子中心處施一水 上, 平力F,使其爬上階梯,若輪子不變形,回答下列問題: (1)輪子在受到一水平力F,但尚未脫離地面,呈靜態平衡時 輪子受到哪些力?列舉並繪出其力圖 (2)承上題,列出輪子所受垂直與水平分力的方程式。 (3)以輪子與階梯的接觸點點為參考點,列出力矩方程式,在輪子中心處最少需施力多少 才能使輪子脫離地面? 《 《指考》

請問第三小題怎麼寫?求詳解 謝謝🙏

p 相關題型:單元練習 5. ~7. 範例 2)等加速直線運動的基本公式 一質點作等加速直線運動,在t=0時以初速度 20 m/s由 x=5m處朝十x 方向移動, 加速度量值為4m/s,方向朝-x方向,試回答以下各小題: , (1)在t=3s時,質點的速度為何? (3)質點朝+x方向移動的最大位移為何? (2)在t=3s時,質點的位置坐標為何? 2 1 V+Vo 「解題關鍵:等加速直線運動最常用的公式:V=Vo+at 、AX=Vot += afts t、V=val +2aax 2 "V=Vor at 未速 - P- Po達長 x間 5+4 0749 「14旨,作为一加官 - 10-147) 二 8 # X mo 未份量: 71量+7 TEROX = Vot + that? t zoxht 2 x -4.9 X OS ORO 60+1-18) = 42 2 1 6 7 it 1. 拉 tn ph 右击始的造上它 son m就回

請問一下，第五題的解答為什麼會把直尺質量放在15公分處？他怎麼知道要放那裡？

O 皆為零, 恆,即在 時變率都 0 53 軍動時, Li 內 1X、(DO:擺鏈所受合刀的刀问日 "< 日 向圓心O點。 (E) O:擺錘所受合力指向O點,其合 力矩為零,故角動量守恆。 4. 由F=ma→T-img=mx0.2g =T T= →T=1.2mg,其對O點所產生的力矩 R = 1.2mg Xr=1.2mg x = 0.6mgR。 2 5. 設直尺的重量為W,其受力圖如附圖所 示由力矩平衡可得W×5=50×5= W=50(gw),故該直尺的質量為50g。 0 15 cm 20 cm 25 cm 30 cm 5 cm 5 cm =L丙 4. (B) 50 gW W mu GMm mV2 6. (1)由 巴 R LR mielge = 9) 1 2 = GM, RS-N;=-Ź → V=(- E ( OR → N-=- - 1 2 o 1

有人會解這個嗎？想知道答案

5. (Ch. 14 - Problem 81 in Wolfson) Two loudspeakers are mounted 2.85 m apart, pointing in the same direction and producing identical sound waves of a fixed fre- quency. You're standing 10.0 m from the speakers, on the perpendicular bisector of the line between them. You move in direction parallel to the line between the speak- ers and find that the sound intensity diminishes, reaching a minimum when you've moved 2.44 m. If the sound speed is 343 m/s, what is the frequency of the sound waves?