求解第十一題🙏

EC 料,2018年3月,平均指一塊錢比特幣所需電能約為2.5 x 10千瓦小時。若以250 套電腦 |_人」,根數位貨幣網站 Digiconomist 的資 設備挖礦,每套電腦消耗的功率均為500瓦特,則 為了挖到一塊錢比特幣,挖礦設備至少需 持續工作約多少小時? 500 w gen) y 2101024x10W) = 1023370 (A) 100 (B) 150 (C) 200 (D) 250 (E) 5002 textooxtx 10 2X -->00 = x = 2.5x 104 kw .hr t=200 11. 空氣污染物PMo.5 顆粒的沉降平均速率為10 - m/s,請問在高空1公里處等速沉降掉落,約 需要幾天? (A) 1天 (B)2天(C)3天 (D)5天 (E) 10 天。 (108 學測改】答: 30 FIO 10 10 一一一 。 RED 8.64 12. 某外星人所使用的長度單位為中,時間單位為O。當其來到地球時,發現和地球的單位比較, 16 = 2.50 公尺,10 = 5.50 秒。若此外星人在地球上以1.10x10*e/C的速度行進,這速 度相當於多少公尺/秒? (A) 5.00 x 10? (B) 1.10 x 108 (C) 2.42 x 108 Da 答 (D) 3.00x10° (E) 5.00x10%。 26410 10 (108 國改」目: ) : DE M=T000 1999 8110 x 106 s. Isti luxcobs I LONorx 2.8315 :A h加速器,同步輻射加速器可將電子加速到接

求解！

737 Two masses are joined by a massless string. A 30-N force applied vertically to the upper mass gives the system a constant upward acceleration of 3.2 m/s2. If the string tension is 18 N, what are the two masses? apety, litly

想請問大家為什麼我這樣算是錯的🙏謝謝～

1925 ~~ 數的口分比 4 x 10096 30 3 「奈米顆粒」一般是指粒徑(直徑)為1 mm 到100 mm 的微 小粒子。單一個奈米顆粒含有數個至數十萬個原子,奈 米顆粒愈小,則其內含的原子數就愈小,但是出現在表面上, 的原子數占總原子數的比值卻愈高(如同所示),這使得由 奈米顆粒組成的物體表面和外界之間的原子交互作用大為增強,結果產生一些異常 的表面效應現象。以金的球形奈米顆粒為例,若其粒徑為10 nm,顆粒中所含的原 子數為27000 個,則其表面的原子數占總原子數的百分比值為 (A) 13.3% (B) 33.3% (C) 53.2% (D) 66.7% (D) 79.8% 卖的組同 就是愛比 原子模型 原子論 最早被没 晚被發現 葡萄乾布丁 出電子 原子行 合兩者! 由茶席 A

請問一下第10題的第四小題 解答是不是錯了？？

W = 2x (B) aca hk 5 牛頓運動定律的應用 概念,地球自轉 若假設地球為正圓球體,且半徑為R、自轉週期為7.下列敘述何者正確?(多選) (A)地球上 任意一點對地軸的角速度皆為 GQ 處向心為 (D) 緯度0處因地球自轉的切向速度為2mRese辯度6歲的向心加速度為 會:20 T (TE) T 2元 (B)赤道處的向心加速度為 T 4元R ME S 0 三 Lsinst w ² =gtank Loosol w A T2 4R²R coso 概念,雖動擺 m mg-N=mão T2 9. 如圖所示為遊樂場中常見的旋轉吊椅示意圖,若鏈條與鉛直線夾37度,鏈條長 Lisinsh=R 度為L,則此時的角速度為6 T Tros 3% = ng tangha- g Tsihn = mac Rw =gtansh 10某彈簧的原長為45公分,將一端固定在天花板上,另一端懸一個質量為20公 斤的小球時,彈簧伸長4公分。今以通過固定端的鉛直線為軸,使該物體等速 率旋轉,如圖所示,此時彈簧伸長5公分。設重力加速度為10公尺/秒?,則: ,5 (1)彈簧和鉛直線的夾角= 3; 鉛 k.0,04 -> K = MAX 5000 " (2)彈簧之彈力為 2XU 牛頓; (3)圓周運動的向心力為10 牛頓; FC = Tsino = 250 x singh = 100N (4)圓周運動的速率為 公尺/秒,角速度為平弧度秒,週期為”及九秒。 a c=R 如圖所示,A、B兩球質量均為11,繞同一鉛垂線在同一水平面 (近的外貌的夾角為30度,B球與鉛垂線 200 e 2000 Tsino=mac Teoso = mg T = SORR X 0,05 = 250N 25000so =2000 caso = 4:39=0 | | 150-28 ac &c=25/615) 7,5x0,05 =1²

範例4圈起來打星那裡是為何呢？

F2 2 s,而有 Psy 10。 77 在上张力及之反射及問題,下列設述何者正確? 者之一的要於牆上,則自牆反射之波與人及振動方向相反(B)若之一端緊 於一变至可忽略的小選,不要套在一細光,骨桥上,則自现反射之波與入射波振動 方向相同(C)若甲繩之一端連接一線密度較小之乙,則在交接處 早上之人 度與反射波振動方向相反(D)若甲師之一端連接另一線密度較大之乙,在交按 處甲鏈上之入射波與反射波振動方向相同(E)不論相的南_4線密度大小,II, 在交接處人與透射波振動方向相反。 AB 自 列 10 31 範例4解析不同維線串聯日寺的波動傳遞 里元車 將粗細不同的彈性繩串聯後,固定於兩牆面之間,如右圖所 示。已知的線密度為4日,細繩的線密度為日。今敲擊租、 如兩靈的交接處產生橫波,則粗、細繩上的反射波首次相遇的位置位於何處? 2. 1 1 L 3 L D交接處右方 (E) 交接處。 42 (6)交接處右方 題壁波動在同一彈性繩中等速度傳播。 (1) V = E F=const vocht v = t=y au 4 L-X AL tv zy uz | Vi=v Vz { v2=2V -3 A - B兩等長之繩連接如右圖所示,設繩共長2L。在 安點C振動,同時產生兩脈衝,一經細繩A傳遞, 三粗繩B傳遞,兩脈衝經兩壁反射後,最後在離C點為x之粗繩上,兩脈 則B、A兩趟的質量比為何?

17題求解

1. 假如把原子核放大成原子筆筆尖上的金屬球大小,則原子的大小成比例放大後,與下列那一 種的大小差不多? (A)乒乓球 (B)籃球(C)截面為運動場大小的球(D)截面為臺灣 大小的球 (B)地球。 Ex 10 Cont[m] = lookom

想問這題怎麼判斷是16😅

和 kk 水面工了| 和 AQcon , 以本下點 0. ( 紀共伺蟬 加 N4 (B)S 為區改x 、則水渡邊為為和em 16 WAb GO0還 文一vU 1

第七題的a 不太懂題目意思 有人可以幫幫忙嗎

肌(史各3 。 和 2 IFig. 2-16, an electron with an ”Nonaccclcratng AcceleraU initial_velocity uo三3.70x 105m/S Tegion region centersaregionoflength工三2.30 cm where it is electrically accelerated- Tt emerges With 三和40x107m/S. What is its acceleration。assumed Path 5f constant? electron 3 A driver increases the car speed ata cons ate_from 15 km/h to 4人0一 人 Figure 2-16 Problem 2 (3) How mucn user the vehicle travelfrom Start to Stop: hen ded toward each other along a track W 10”Two trains are heai ( the conductors suddenly notice each other. Figure 2-18 glves their velocities 35 functions oftime f as the conductorS Slow the trains. The figure's vertical scaling is Set by 人三 60 m/s. The slowing processes begin when the trains are 320 m apart. What Figure 2-18 Problem 10. is their separation when both trains have stopped? 時 宣 一snrnnnrlevelat 34 A _ rock climber acci- dentally allows a piton to fall freely from ahigh point on the ITock wall to the valley below him at time /==0. Then, after a 全Dort delay,his climbing partner, whois15mhigheron

18題，感謝

10. [2D and 3D motion] Show that the potential energy U(r) ofFa particle of nass jat aa distance r(> 員 from a planet of Inass 4 and radins 戶話 11. [The cross product] Caleulate the cross product A x B, assuming that A and B both lie in the x-y plane and have the respective nonzero components 4,, 4, and 妖,, 且, 12. [Angular momentum] Show that 主r, the instantaneous position ofa particle of mass mu with respect to a certain origin O, is parallel to its acceleration dv/吧, then the time Tate of change of the angular Inoimentum L with respect to the given origin vanishes 13. [Theorem 了 Show that the torque-angular momentum formnla _箇 7二 is also valid for a two-particle system 放 the origin lies at the center of mass 14. [Theorem IIH] Two particles of respective Inass ml and 2 are connected to the ends of amassless rod and Inove in the uniform gravitational field g ofthe earth. (a) What is the acceleration of their center of nass Telative to a Newtonian origin O? (b) Show that the angular Inomentum of the two particles about their center of nass 生 aconstant of the motion. 15. [Moments of inertia] Calculate the moment of inertia ofathin, uniform rod of mass m and length / about an axis perpendicular to the rod and at a distance q from one end. 16. [Rotation about a fixed axis] Consider the rotating cylinder in Figure, and suppose that A7 sg, Fo 三 0.6 Nt, and @ 二 0.2m, Calculate (a) The torque 7 acting on the cylinder (b) Ti ngular aceeleration q of the cylinder 17. [Work and kinet: instant Totat eenergy] A 40-kg homogeneous sphere of radius 10 cm is at acertain about ashaft through its center at 600 rpm. Assuining that a constant fric itude ets so that the sphere comes to rest in 10 seconds, Calculate th tional torque ofthis torque. 18. [The physical pendl end and allowed to oscillate freely in a horizontal plane (see Figure) m] A uniform Tod of Inass ru and length / is suspended at one (a) What is the period of this physic lpendulum for small amplitudes? (b) Ithe velocity u0 of the mass ce Hulum is initially released at rest in a horizontal position。what is the er at a subsequent instant when the Tod is vertical? (ec) Calculate the vertical and the horizontal components of the force on the rod at the point of suspensic 19 and rotations] Analyze the motion of a homogeneous sphere of mass 和7 and Tadius dq, which rolls without slipping down a fixed inclined plane of angle # 20. of angular momentum] A Inan has ainoment of inertia 五 about the = axis. He is originally at Test and standing on asinall platform which can turn freely. Ifhe is handed a wheel which is rotating at and has anoinent of inertia 了about its spinning axis, determine his angular velocity 放 (a) he holds the wheel upright, (b) turns the wheel out 9 二 90?, and (c) turns the wheel downward, 9 二 180?. Neglect the effect of holding the wheel a distance d away from the z axis

藍筆打勾的這段 需要解釋~~ 我看不懂 --

1. 彈性力 (或彈力) 力作用於物體時,可使物體的運動狀態發生改變,或使 物體產生形狀的變化,當物體受力變形,但在施力除去後, 立即恢復原狀的性質稱為彈性ˋ在正比限度內,當彈筑受外 力作用形變時 ,侯黃會產生一彈力抗衡外乃/: 當彈貸靜止時, 此二力量值相等、方向相反,彈簧的形狀改變量 (簡稱形變 量) 與彈力量全成正比上表示彈貸產生的彈力量值,y仿 相對應的形變量, 比例常數 《稱為力常數(force constant) 。