log_(x-2)(x-5) <2 log.4
x2²-7x+10<4
x ²= 7x + 6 <0
3.
設方程式 xl+logs x =81x²之兩根為a與B,則aß之值為
logx
=t
Tog3
log₁x²x=log+x²3"
1+/090x = 3 + 109-3²
3+41093.
1+ t
4. It xlog x= 之x解為
1000
109 xlogx. Tog,
109x
x4
loov
X
1+1=3 + 4 = 12
O
2
七十七=3t+4
Togx 1-21-4=
t=4-3 = 1
2
=4-109 x 1000 +² = 46-3
1<x<6
X-2 >0
3-1
109x
