我需要all in one第四冊的解答拜託

急❗️請問這題逼選項要怎麼判斷🥺🙏

23.下列各組中,兩化合物沸點高低之比較,何者正確? CANO CHIC C-C-O-C-C N2 0 || CH3CH2OCH2CH3 <CH3-C-CH, (C) CH3CH2CH2CH2CH3>C(CH3)4 CH(D) H2S <H2O All RCOOH R ↗有分手内 7 (E) SiH4> CH4

想問32題

ar C People of all ages all around the world have been touched by Walt Disney's works and inspired by his rags-to-riches story. His own road to success A29 the positive message the company has been sharing with its fans repeatedly: Never give up on a perfect example of your dreams. 30 drawing as a boy and founded he was faced with Born in 1901, Walt Disney developed a passion the Disney Brothers Cartoon Studio when he was twenty-two. 31. many difficulties and failures along the way, Disney didn't lose faith. One day, a sudden inspiration struck him. He created a joyful little character, Mickey Mouse, that saved his shaky career and helped him build his entire fantasy kingdom. In the years that followed, Disney Studios completed popular animated film after 32 countless iconic characters. 動畫電影 32 If Walt Disney were alive today, he would warmly reassure you and introduced that your achievements depend on your 33 and willingness to keep trying. He would also tell you that sometimes the key lies within your most unexpected daydreams. If you can dream it, you can do it.

（第一張照片）守恆的概念是沒問題的，但換符號好像有點問題，mg是怎麼換成mV/r的？？？還有a是怎麼換成V^2/r的？？？感覺是我前面換算學得不太好的關係🥺 （第二張照片）想知道c選項的算式是怎麼來的？

範例3 圓周運動的力學能守恆 雲飛車是一種常見於主題樂園中的遊樂設施, ao 其軌道通常有如圖所示的迴圈。若考慮正圓的迴 圈軌道,且軌道可視為在一鉛直面上,雲霄飛車 的車廂在沒有動力驅動之下,沿著軌道內側繞行, 且軌道只能提供向心力,摩擦阻力可忽略,重力 加速度為g,則當車廂可沿整個圓圈軌道繞行時,車廂在軌道最低點的加速度量值至少 為何? (A) 2g (B) 3g (C) 4g (D) 5g (E) 6g 向心力: V₁ F=mg= m JJR VH R + a₁ = JEJR (JSJR) R V₁ R 1=5g A.0) 願選一條長為R的繩子綁住一個石塊,讓石塊一開始在鉛直面上作圓周運 動,石塊的位置可由石塊—圓心連線和水平線夾角表示,如右圖所 Mo 示。若石塊在最低處的速率改為 7gR g為重力加速度,則石塊轉 2 到何處時會脫離如圖所示之圓形虛線軌跡?(已知sin37°=0.6) (A)=30° (B)=37° (C)=45°(D)=53°E=60° R my mg cose 79R 2 ① 力学能守恆 /m() :/mv+mgal1+sine) myR 2 → v² 1 gk (3-4 sino) ② 圓周運動(向心力:張力、動) T+ mg sino - V = 1mg (3-4 sino) →繩鬆⇒7:0 →脫離:與最低點高度差h " R+R Sind ⇒ 0+mg sine = 1 mg (3-45/40> : R(1+ Sine) => sino 0-300 【107. 指考】

請問有人有第四冊all in one解答嗎

有人有龍騰版all in one的二冊的解答嗎？ 急需！！！謝謝😁

習通型高級中學 英文: All in One 編著者/匡德勳、張秀帆

請問有人有all in one 第二冊解答嗎

請問這要怎麼算

a10值有多少種可能? (A) 10 (B) 11 BO 157147 14個1.27 2. 28 safing challenges 9. 將30顆乒乓球分裝到甲、乙、丙三個盒子中,規定不能有空盒,且甲、乙兩個 盒子裡都須裝奇數顆球,則所有符合條件的分裝方法有幾種? (A) 105 (B) 120 (C) 153 (D) 378 奇奇偶 =1050 (C) P2 (D) 20 A10 同時擲三顆不公正的骰子,若已知其點數 x,y,z 為偶數的機率依序為 1.2 23 , ,

想問下面兩題 需要完整解答方式跟流程．

*甲乙2人比赛下棋(沒有和局)約定好:若甲先獲得 三勝則算甲贏,但在甲三勝前已能連續2勝則算乙 贏,若第一局是甲獲勝,間接下来比賽的勝負過程有7種 問:why. 甲 甲 甲 甲 乙 How to 解? *從1~20的20個整數中,取出了個相異的數a.b.c,使其成 等差數列,且acbcc.則序組(a.b.cv)取法有40種. (1.2.3)~(18.19.20)→18組 (1.3.5) ~ (16.18.20) → 16組 (1.4.1)~(14.17.20) →14組 (1.10.19) (2.11.20) → 2 組 P₂ = than i : 一定要all列出? 有無更快 soln.

求龍騰all in one 第二冊第4課解答🙏🥲