17題求解

1. 假如把原子核放大成原子筆筆尖上的金屬球大小,則原子的大小成比例放大後,與下列那一 種的大小差不多? (A)乒乓球 (B)籃球(C)截面為運動場大小的球(D)截面為臺灣 大小的球 (B)地球。 Ex 10 Cont[m] = lookom

非選第8題為何不能那樣算？ 答案是紅筆寫的

=1:2:9 Co>_ > Com | 10 (BC H AT C:C:C9=1:2:4 AT-40°C - consily Ca Hat A /C= | 2 4 50 (B) GES m 1 (C) EC- AT 1 1 || 1 > J Te: ATE : AT --: 20 A. B 0 60 8 互動式教學陆義·選修物理(上) (D) 3 質量 0.25 kg 的立 C (A) se: Scism= 20 100 溫度為10°C。 =: 5:2:8 的沸水中取出後 H H=const. AT 忽略热量的散逸 C 4.2 kJ/kg·°C) 一:一=4:2:1 24 (A) 400 (B) 800 二、多重選擇題 y (BD) 4 若兩物體之熱容 (A)升高10°C 所 VI HETALL 3:1 D)升高1 3.2 (B)兩者是比為2:9。 (KG) 5 有A、B兩種固體物質,其溫度T與加熱量H的關係 T("C) 如右圖所示,則下列敘述何者正確? (6000 (A)溫度變化相同時,A物所需的熱量為B的0.4 倍 (B)A物的熱容量比B物大(CA物的熱容量為3 *H(cal) | 150 cal / °C (D) B物的比熱為7.5 cal g·°C (E) B物 的比熱一定大於A物。 三、非選擇題 26 容器內原來裝有20°C的水50克,今倒入100°C的水60 克,若已知容器散熱 400 卡,則平衡時水溫為 Lo 50*\x20 + 60 x\*\00-400 - MOXIXAT. 1000+6000-400 = 110oT cittoo=NOAT 77. 體積相同的鉛球(密度 10.2g/cm,比熱 0.030 cal/g·°C)及銅球(密度 8.5 g/cm',比熟 0.090 cal/g·°C)各一,其熱容量之比值為0、牛 (o= 10. 2m x 0.03 °C (1=815m x 0.09 8. 將A、B兩金屬以相同熱源加熱所得的關係圖,如右圖所示, -0.外邊, 設A、B質量均為0.25 kg,熱源供熱100 cal/s,求: .CA=4000 120 (1)加熱 20 可使A溫度達300°C-350 = jo 200 +50 3000 C 200 (2)當B的溫度為300°C時,A的溫度為350 40 307\u3000 加熱時間(s) (3) A質量100g B質量 50g做成合金之比熱為 7 2.4 0.067 cal/g © 進階題 a lx 100 xDT + 0.05 X 40 XDT = 0.15 x 34 x DI 16=0.15S; SE-2. 4 SBS SHO 29. 當A與B混合時平衡溫度為40°C,當B與C 10 十= 0~154 「液體」質量(g) 混合時平衡溫度為60°C,則A、B、C三者混 溫度(°C) A 合,平衡溫度為 20 30 (不計熱量散失, 數據參考右表所示) B 40 50 立 10 將一枚熱水倒入絕熱量熱器中,量熱器中的冷 C 30 180 水溫度升高了5°C,再加一枚同樣的熱水,溫度又升高了3°C。假設熱量沒有散 失,再繼續加入了同樣熱水,此量熱器中的水溫將再上升 °C。 度 400/ A 20 = 20calle 0 40 10

想問這題怎麼判斷是16😅

和 kk 水面工了| 和 AQcon , 以本下點 0. ( 紀共伺蟬 加 N4 (B)S 為區改x 、則水渡邊為為和em 16 WAb GO0還 文一vU 1

第七題的a 不太懂題目意思 有人可以幫幫忙嗎

肌(史各3 。 和 2 IFig. 2-16, an electron with an ”Nonaccclcratng AcceleraU initial_velocity uo三3.70x 105m/S Tegion region centersaregionoflength工三2.30 cm where it is electrically accelerated- Tt emerges With 三和40x107m/S. What is its acceleration。assumed Path 5f constant? electron 3 A driver increases the car speed ata cons ate_from 15 km/h to 4人0一 人 Figure 2-16 Problem 2 (3) How mucn user the vehicle travelfrom Start to Stop: hen ded toward each other along a track W 10”Two trains are heai ( the conductors suddenly notice each other. Figure 2-18 glves their velocities 35 functions oftime f as the conductorS Slow the trains. The figure's vertical scaling is Set by 人三 60 m/s. The slowing processes begin when the trains are 320 m apart. What Figure 2-18 Problem 10. is their separation when both trains have stopped? 時 宣 一snrnnnrlevelat 34 A _ rock climber acci- dentally allows a piton to fall freely from ahigh point on the ITock wall to the valley below him at time /==0. Then, after a 全Dort delay,his climbing partner, whois15mhigheron

請問保守力這個東西要怎麼解釋它 它有方向性嗎？

想問這題怎麼做？謝謝

生生 和 朮 時 AN 210& V) 4Img& 0 3 Go + 夫人有圖所二 , 將一小于懸持在一細繩下 已知當小球從最 全還上衝天高度hr二2作生抽的盡力和變成夫 條 設摩擦力及空氣阻力皆可忽略 , 重力加速度為g,則小球 的初速 V0 為何 ?

請問為什麼要這樣算

人 aced on aat surfaoe (retion coefreient go.U are cowneeteavy sseeeg, nitially, the spring has an extension ofl mand both masses are st rest GYves Vsx so 儿 masses are equal. mm二1 kgo and the spring constantk-9.S No watss Ane waxseses compression ofthe Spring? (CAD)1m (Bosm Go6m (COD04m 一CE None ottne above- 喘終昌A2 AT (229 耿iRMBUEWOBEEA RAR-

18題，感謝

10. [2D and 3D motion] Show that the potential energy U(r) ofFa particle of nass jat aa distance r(> 員 from a planet of Inass 4 and radins 戶話 11. [The cross product] Caleulate the cross product A x B, assuming that A and B both lie in the x-y plane and have the respective nonzero components 4,, 4, and 妖,, 且, 12. [Angular momentum] Show that 主r, the instantaneous position ofa particle of mass mu with respect to a certain origin O, is parallel to its acceleration dv/吧, then the time Tate of change of the angular Inoimentum L with respect to the given origin vanishes 13. [Theorem 了 Show that the torque-angular momentum formnla _箇 7二 is also valid for a two-particle system 放 the origin lies at the center of mass 14. [Theorem IIH] Two particles of respective Inass ml and 2 are connected to the ends of amassless rod and Inove in the uniform gravitational field g ofthe earth. (a) What is the acceleration of their center of nass Telative to a Newtonian origin O? (b) Show that the angular Inomentum of the two particles about their center of nass 生 aconstant of the motion. 15. [Moments of inertia] Calculate the moment of inertia ofathin, uniform rod of mass m and length / about an axis perpendicular to the rod and at a distance q from one end. 16. [Rotation about a fixed axis] Consider the rotating cylinder in Figure, and suppose that A7 sg, Fo 三 0.6 Nt, and @ 二 0.2m, Calculate (a) The torque 7 acting on the cylinder (b) Ti ngular aceeleration q of the cylinder 17. [Work and kinet: instant Totat eenergy] A 40-kg homogeneous sphere of radius 10 cm is at acertain about ashaft through its center at 600 rpm. Assuining that a constant fric itude ets so that the sphere comes to rest in 10 seconds, Calculate th tional torque ofthis torque. 18. [The physical pendl end and allowed to oscillate freely in a horizontal plane (see Figure) m] A uniform Tod of Inass ru and length / is suspended at one (a) What is the period of this physic lpendulum for small amplitudes? (b) Ithe velocity u0 of the mass ce Hulum is initially released at rest in a horizontal position。what is the er at a subsequent instant when the Tod is vertical? (ec) Calculate the vertical and the horizontal components of the force on the rod at the point of suspensic 19 and rotations] Analyze the motion of a homogeneous sphere of mass 和7 and Tadius dq, which rolls without slipping down a fixed inclined plane of angle # 20. of angular momentum] A Inan has ainoment of inertia 五 about the = axis. He is originally at Test and standing on asinall platform which can turn freely. Ifhe is handed a wheel which is rotating at and has anoinent of inertia 了about its spinning axis, determine his angular velocity 放 (a) he holds the wheel upright, (b) turns the wheel out 9 二 90?, and (c) turns the wheel downward, 9 二 180?. Neglect the effect of holding the wheel a distance d away from the z axis

想請問這兩題的詳解

和 倆 *"易 1@ 二 2傘g 和加 了人 <易士旦鹿未臣天轎單腊, 時評所螞誤悶 二 電扯二宮點。基如閱斑謂陋時漲 大丁吧 1 艙呈一事。上#嶄店箇上

藍筆打勾的這段 需要解釋~~ 我看不懂 --

1. 彈性力 (或彈力) 力作用於物體時,可使物體的運動狀態發生改變,或使 物體產生形狀的變化,當物體受力變形,但在施力除去後, 立即恢復原狀的性質稱為彈性ˋ在正比限度內,當彈筑受外 力作用形變時 ,侯黃會產生一彈力抗衡外乃/: 當彈貸靜止時, 此二力量值相等、方向相反,彈簧的形狀改變量 (簡稱形變 量) 與彈力量全成正比上表示彈貸產生的彈力量值,y仿 相對應的形變量, 比例常數 《稱為力常數(force constant) 。