2~4求解 第四題其實會算但不知道為什麼一直是錯的🤧

2. i=√-1,將~1+(N-2)ì化成極式,使形如(cos⑥+isin 0),P>0,0≤0<2元, 則有序對(y, 0) = _____ 3183 心 = 8√4 3. &£a,be R,i = √=1,z₁ = 2-√3a+ai, 2₂ = √3b-1+(√3−b)i · #|²|=|z₂|' 且Arg(2)=^,則有序對(a,b)= 2 不 (Bonsa) + a+= (136-1)+(155b) 2-3a+G5 36-415-4 Jaskie 中 TU 4. 設z 為複數,且|二二)|= Arg(二)=²,則z 的極式為 2 2 Z 3 √ V (55) 44 F 54 dal 4 7

想問這題 錯兩題是4-2=2為什麼是超過四分？

上午11:26 */ 62 X A X 名師課輔網 - 超級緊急.. qask.com.tw 口 < : 數學超級緊急數學機率6 [已解决 500點 2答 高中 0 發問者 Lucky 等級 發問時間 2013-06-02 18:09 回答次数 1 某次考試共有10題是非題每題答對得1分答錯倒扣1分,不作答得0分 設甲生確訂作答的有4題,其餘6題都不經考慮猜題,如果甲生4確定會的4題都對了 那麼甲生得分超過4分的機率為?Ans. 11/32 直讀成為朋友中第一個說這個讚的人。 共2個回答 TOP 數學Frank老師 等級 回答時間 2013-06-06 09:45 回宫里隋 發問次數 0 回答次數 152 同學您好,關於您的問題回覆如下: 3 甲生確定會的4題都答對了,所以這四題確定可以得到4分 9 9 其餘6題不經考慮猜題,其結果可能有以下幾種: 1. 對6題,錯題可得6-0=6分(甲生超過4分) 2. 對題,錯1題可得5-1=4分(甲生超過4分) 3. 對4題,錯2題→可得4-2 = 2分(甲生超過4分) 4. 對3題,錯3題→可得3-3=0分(甲生刚好4分) 5. 對2題,錯4題可得2-4--2分〈甲生低於4分) 6. 對1題,錯題可得1-5= 4分〈甲生低於4分) 7. 對題,錯6題可得Q-6=-6分(甲生低於4分) 3 因此,只有前三種情況會讓甲生得分超過4分 對6題,錯題,共有CS = 1種情形 對5題,錯1題,共有9 xC = 6種情形 對4題,錯2題,共有Cx = 15 種情形 6題是非題全部作答,共有2 = 64 種情形 6 9 1 -- (超過4分) = P(對6題,錯1題)+ P(對5題,錯題) + P對題,錯題) co eg xerxes 26 20 1 6 15 22 11 64 64 64 4 64 64 32 - + + 26 - =-+-+-- + + = - - - 以上說明,謝謝您的提問 」

第十四題－三角函數 有大大可以幫我導出來嗎？謝謝

為一個以 須取多長的一 B 1 例題1 計算。但 () 對應的弧長為 表示。 一的值,求 解答: 在第二 o 13. 已知一個三角形的兩邊d=2 與b=3 以及央角 C = 60°。求c邊的長度。 1. 正弦定律 正弦定律是說,若a,b,c 為一個三角 形的三邊,它們的對應角為A,B,C,則有 繼續 sin C ask sin A sin B b b C a 請利用下面的兩個附圖與恆等式 sin(T-9) = sing 推導出此定律。 其中 以及 A A C h b b A h b 公式。 B. C B a C. a 指數函數 數

請問這題為什麼能這樣假設餘式？

+4-03 b = -2 f(2)= 5= 29th 類題 人 Ask 答 2 設(c)為一多項式,若(x)除以x-2的餘式為8,f(x)除以x-2x+3的餘式為: 則(c)除以(x-2)(x-2x+3)的餘式為 f(2)=8 F(x) = (x-2). Q(x) +8 火热活因式分解 f(x) = (x ² = 2X+3) . Q'(x) +X-6, ** $175453 => f(x) = (x-2)(°-2x+3) -Q() + (x*-2x+3).m +x-6. 焦點4 因式定理 1. 因式定理: 設f(x)為一多項式,若ux-b為(x)之因式,其中a、b為實數,a+0, El f(x)=(ax - b)X Q(x) Wifi =0。 2. 因式定理的推廣: (1)若-a、X-b為f(x)之因式,則 为

根本看不懂啦＼(￣▽￣;)／

Your report should follow these guidelines, although you may choose how you present it: How to Write a Mathematics Report In writing your report, remember that you are writing up a mathematical story and so, like all good stories, it will need a beginning, a middle and an end. More formally, the main components of this writing style are: Introduction, Formulating the Problem, Solving the problem, Discussion of Results, and Conclusion. We will now consider some of the detail in each of these aspects. Introduction This is the beginning of the story. Give a brief explanation of what the problem is about what the goals of the report are and what will be presented. Assume that your reader does not know what the problem is about or how to solve it. Formulating the problem Translate the situation into a maths problem. Explain how you will begin to solve the problem and break it into simpler stages. Discuss any assumptions made. What quantities are variables and which values are fixed? You may use sub-headings if they assist you. Solving the Problem Show any calculations and mathematical reasoning that you use. (Assume that your reader does not know much maths). Do not show the same types of calculations repetitively. Just give one or two examples of a calculation and then put the rest of the results in a table. Use diagrams or graphs if they assist you. Make general remarks about what you observe in your calculation results and, possibly, why. You may want to criticise your work and go on to improve it in the next section. Explain what you will do next and why. Discussion of Results - Evaluate and Verify Summarise your results if necessary and refer to your mathematical reasoning. Justify procedures used. Interpret your results. First, are they reasonable or does something not look right and need further investigation or checking? Is there a decision to be made? Here is where you should present the decision-making process. Evaluate the strengths and limitations of your solutions. Conclusion Summarise your findings. Refer to the problem outlined in the introduction. Make sure that you answer the question that was asked. Make recommendations. No new material should be presented here.

英文跟數學都好的學霸QAQ 會用到微積分

IFY Mathematics Coursework Part1 [d] Divide the area under the curve betweenx=1andx=5ito more rectangles using the same process and work out the sum of areas of the rectangles formed. You can use Excel for this. Does your observation nm part [c] seem to be confirmed? Explain why this happens. [9可 (0) (20) (3,0) (40) (220) Figure 3 Summary and conclusion Write a short conclusion (maximum of 100 words) explaining what you have discovered in these tasks. [6] Version1 1920

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求第16題 A C差一個did 有什麼分別嗎？ 不懂OAQ

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