請問這個是怎麼算出來的，謝謝🙏

9 1. 如果以原子為組成物質的單元,則 直徑為0.1毫米的一粒細砂含有的原子數目約為10 的幾次方? (A) 10° (B) 10° (C) 10 (D) 1017。 學測 1x10-3 with n 反斗方自己急于。教学 10 10 (66

求詳解

(E)此力可解釋蘋果從樹上掉下來的現象 (C)密度相同且質量皆均匀分布的大、小兩個實心球,半徑分別為2R 及R。已知半徑為的 球,其體積為,若小球的質量為1,當兩球以如圖所示的位置擺放時,兩球間的重 4.| - 4.0 P.71 D 4 Pl 力為何? Gina? R? | |- (A) 3m - 8Gm? 2R 2R (B) R 40 = 15m D 己 4) A = 3 mx 4 m² 在 G 43 im (53) 3m Gina k2 (C) 25R 8Gina G4mxm VSR whe 人 -- with w (D) 25R 16Gina? o (E) 25R , 2n

第十三題，不太懂要怎麼計算那段繩張力

mg A V (30) (8) or (D) (b) ( 1 V Vz 質量同為m4"B、C三球,以長度均為L的三條輕繩連接,使其 Tistro 繞O點作等速圓周運動,假設A球的速率為y。試回答下列問題: 11. 求B球的角速度為何? C v = 2 With 2v 2L L 2L L ( 的 12. 求C球所受的向心力量值為何? 3my? 人。 (A)- (B). (C) (D) mL (E)jm-L 3L L 3 2 zm ve TAB-TBC L 2my? 3my? Smy? 7 (B) L (E L L L 3 M3V my? my2 LL zmu? C: 3m va 13 求 AB 繼張力的量值為何? CA (A) (C) (D) mL (6)mL (D) -mv²L 0

21題 教教我QAQ

Section 11.3 Angular Momentum J-s behind rmv a he ur 265 = ? a ter 30. Example 11.1: A 58.1 Iw COMP string and whirled at 18. Express the units of angular momentum (a) using only the funda- momentum of magr mental units kilogram, meter, and second; (b) in a form involving the circular path. Fir newtons; (c) in a form involving joules. marw horizontal and (b) the 19. Use data from Appendix E to make an order-of-magnitude esti- 31. Example 11.2. A stai mate for the angular momentum of our Solar System about the Max 27 the end of its lifetime galactic center. mu = 17.293 of radius 4.96 X 10' 20. A gymnast of rotational inertia 63 kg•m? is tumbling head over heels dwarf of radius 4.21 with angular momentum 460 kg•m?/s. What's her angular speed? 17.99 acted on the core, fine A 660-g hoop 95 cm in diameter is rotating at 170 rpm about its 32. Example 11.2: Astro 22. A 1.3-th-diameter golf ball has mass 45 g and is spinning at central axis. What's its angular momentum? L: 1W=0-66*(0-95) x 140x277.10 km and determin core that collapsed to 3000 rpm. Treating the golf ball as a uniform solid sphere, what's ing with a period of 4 its angular momentum? 18-3 33. Example 11.2. The s 10-598 rpm With her arms outstre Section 11.4 Conservation of Angular Momentum tational inertia is 3.5 23. A potter's wheel with rotational inertia 6.20 kg•m? is spinning (Fig. 11.6b), her rot freely at 20.0 rpm. The potter drops a 2.50-kg lump of clay onto her final spin rate? L = 6 2 x 2-1 = 12-99~13 - 2x2 22 13= 60.48)" x 2.5 W W = 2 . X z W = 20x2T 60 ²2.1 ~ 1 12.574

第21題 到底要怎麼寫ಥ_ಥ

Section 11.3 Angular Momentum J-s behind rmv a he ur 265 = ? a ter 30. Example 11.1: A 58.1 Iw COMP string and whirled at 18. Express the units of angular momentum (a) using only the funda- momentum of magr mental units kilogram, meter, and second; (b) in a form involving the circular path. Fir newtons; (c) in a form involving joules. marw horizontal and (b) the 19. Use data from Appendix E to make an order-of-magnitude esti- 31. Example 11.2. A stai mate for the angular momentum of our Solar System about the Max 27 the end of its lifetime galactic center. mu = 17.293 of radius 4.96 X 10' 20. A gymnast of rotational inertia 63 kg•m? is tumbling head over heels dwarf of radius 4.21 with angular momentum 460 kg•m?/s. What's her angular speed? 17.99 acted on the core, fine A 660-g hoop 95 cm in diameter is rotating at 170 rpm about its 32. Example 11.2: Astro 22. A 1.3-th-diameter golf ball has mass 45 g and is spinning at central axis. What's its angular momentum? L: 1W=0-66*(0-95) x 140x277.10 km and determin core that collapsed to 3000 rpm. Treating the golf ball as a uniform solid sphere, what's ing with a period of 4 its angular momentum? 18-3 33. Example 11.2. The s 10-598 rpm With her arms outstre Section 11.4 Conservation of Angular Momentum tational inertia is 3.5 23. A potter's wheel with rotational inertia 6.20 kg•m? is spinning (Fig. 11.6b), her rot freely at 20.0 rpm. The potter drops a 2.50-kg lump of clay onto her final spin rate? L = 6 2 x 2-1 = 12-99~13 - 2x2 22 13= 60.48)" x 2.5 W W = 2 . X z W = 20x2T 60 ²2.1 ~ 1 12.574

想問問這題～謝謝

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［高二物理 圓周運動］ 請問這一題的D選項是如何算出來ㄉ？ 感謝_(´ཀ`」 ∠)_

COLD > ABC Si > slt 16 mwv= mg 平, 3. 維動擺之擺長不變,而幅角由37變為53 時: EB(A)向心力變為9倍 (B繩之張力變為一倍(0)旋轉速车變為 73 Using a sing 3 & → 倍(E)旋轉半徑變為一倍 2 → T- (D旋轉 9. // - 週期變為 {T COSE = mg Tsin > & well with flu/unfall L11 314 3 mg 8/3 = #grtano 培 Rsino Vig m tano 4.3 mtano a & 4 16 (1) coso a 416 X La = m ST w T 上 9 > y = > tano = 選題 十: - y=artano = g

求解🤢

Chapter 3 Falling Objects 3.2 A ball is thrown downward with an initial velocity of +20 m/s. Using the approximate value 10 m/s2 for the gravitational acceleration, find (a) the velocity and (b) the distance traveled at 1-s time intervals for the first 2 s of motion.

第二題怎麼算？🤔

JUN, 11 3 JUSI INar stay with problems longer.-Einstein (二)1. A、B、C三個點電荷分別帶電 20、20、-q,若A、B、C以等間隔d排成一直線 如附圖,則A、B、C三個電荷所受淨電力量值之比為若干? (A) 5:6:7 (B) 5:4:7 (C) 5:12:3 (D) 7:4:5 (E) 7:12:5 A B C 2a d 24 d -9 12. A、B兩大小、質料相同之小金屬球,當距離 r 時測得其相互斥力為12 達因, 如果將A、B兩球接觸後再分開至距離r,其斥力增加4達因,則A、B兩球未接觸前電 量之比為若干? 4 (A) 4:1 (B) 3:1 (C) 2:1 (D) 3:2 (E) 4:3 } r

第一題怎麼寫？🤔

JUN, 11 3 JUSI INar stay with problems longer.-Einstein (二)1. A、B、C三個點電荷分別帶電 20、20、-q,若A、B、C以等間隔d排成一直線 如附圖,則A、B、C三個電荷所受淨電力量值之比為若干? (A) 5:6:7 (B) 5:4:7 (C) 5:12:3 (D) 7:4:5 (E) 7:12:5 A B C 2a d 24 d -9 12. A、B兩大小、質料相同之小金屬球,當距離 r 時測得其相互斥力為12 達因, 如果將A、B兩球接觸後再分開至距離r,其斥力增加4達因,則A、B兩球未接觸前電 量之比為若干? 4 (A) 4:1 (B) 3:1 (C) 2:1 (D) 3:2 (E) 4:3 } r