請問有大神教教我嗎？！我不太會判斷這個 ！謝謝你🤯🥰急需要

Vy=9xt =10x4 斗向拋射的重要性質 = 2×10×16 : 80 (a) 6不計空氣阻力,在水平面將A、B兩球同時同地分別以仰角 V=30+50 =40 (考量水平,克) 37°與 53°拋出,若最大高度相等,如圖所示。有關兩球運動 B 的敘述哪些正確? 最大高度 最大高度相同 ⇒ 鉛直初速、飛行time一樣 (A) 在空中飛行時間相等(B)兩球鉛直方向的初速相同(C)A、B兩球的初速比為4: 3(D)A、B兩球的水平射程比為4:3(E)若二質點同時同地拋出,二質點在空中相遇。 +2X-10X30 RA VAL33XT Yasin ³° : VA Sin 53° = VA 4 在任一時刻,肉球高度相同, VB=3 水平位移苣不同3 =球x相撞. PB : VA (0353°XT 4 16 3x=9 = 4x5 7. 如圖所示,不計空氣阻力,在水平地面上以相同初速,不 60m 同仰角,先後斜拋同一物,第1次和第2次的最大高度分 別為20m及60m且水平射程相同。則有關此兩次的拋射, 下列敘述何者正確?(g=10m/s²) 20m 餘 免蘿田 最大高度較大者 (A)第1次在空氣中停留的時間較長(B)兩次拋射的仰角互補(C)第1次的仰角378 *(D)其初速量值為40m/s (E)水平射程為80m。 & R= 承山 2x40 Sin 30 (0330 80万 = (E 第二次98-6 V=Votat 軌跡方程式 9 0+2 ⇒20160 (Sino+(asè) Yo So 20 Vo Sina 60= 10* Sin (90°013 『體自地面斜向拋出,其軌跡方程式為x²-240x+180y=0(其中以地面為x軸、拋出點的 " 2g Volos *tano,

想問圈起來的地方要怎麼推導出來

V & ox F 7> dx V = Timex xx = x = de 18 a 7+ A d a = lim -- f 又 = d dv ft IVY 2

在第一小題裡面到了環的中心點是不是還具有重力位能-GMm/r？為什麼呢

R √3R m M 2. 有一均質固定圓環半徑為R,質量為M,在環的中心軸上, 距環心√3R 處有一質量為m的質點,(重力常數為G) (1)若質點原靜止,僅受環的重力作用,當質點到達環心處時 其速率為何?B)2:3 (2) 若欲使質點脫離環的重力作用範圍,則質點的初速率至少 為何? 答: 愛車

請問手機橫拍和直拍的差別是什麼？

, 时感應到兩張卡 可以避免重複扣款 17.-18.題為題組 如右圖,你是否曾經拿著手機對著電子螢 幕拍照,卻發現手機畫面不斷閃爍。請根據右 圖,回答下列問題。 J 17.為了瞭解此機制的原理,我們設計實驗方 式如下列選項所描述,請問哪一個選項的 B 實驗比較得不到有意義的結論? 0421 時刻 Tarmetable. 815 開往 經由 Train No Destination 車次 Vian SMISURAT At 4711 STIERE 242台中 8:84 1644 ALAM 車種 Train Type 2 時間 月台 備註 Dep Time Platform Remarks w V:/4 吃 限 全 学號(02:51 354 355 (A)將手機改成錄影模式,看是否閃爍 (B)改用前置相機鏡頭,看是否閃爍 (C)將手機橫拍改直拍,看是否閃爍 (D)調整手機內相機的快門,看是否閃爍 (E)調整手機的 ISO值(感光度),看是否閃爍 SPAAD7817 5分 254 424 0816431 示 CONSHIS 蜜出資車、蠟

想問這題🙏

u 5.一物體質量m,以v的初速從仰角37°的斜面底端沿斜面上滑至最高點再下滑至斜面底 , 若物體與斜面間之動摩擦係數為0.25,重力加速度值為g,則 5V² 对你好 >14 (1) 物體上滑的最大位移為何? (2) 物體再落回斜面底端時的速率為何? 4 x ² x 1/2 = = mg 二 jhmy mgus 37 xo.ry = mg x + 1/7/2 f }/m Fm x10+ n-g mxle = wxh H 6mtime FJ Vo - V a = 8 5

想請問這四題

98. A baseball is hit straight up and is caught by the catcher 2.0 s later. The maximum height of the ball during this interval is: 4.9 m 2÷2=1 XA) B) C) D) E) 7.4 m 19.4 m 38.8 m 19.6 m 122. DA If the x component of a vector A, in the xy plane, is half as large as the magnitude of the vector, the tangent of the angle between the vector and the x axis is: A) √3 B) 1/2 C) √3/2 3/2 D) E) 3 142. Two vectors lie with their tails at the same point. When the angle between them is increased by 20° the magnitude of their vector product doubles. The original angle between them was about: A - B = |A|| B|cos O 2 L² cose = L² cos (0+20²) 2005 = cos@casso. sing sino A) 0 B) 18° C) 25° D) 45° E) 90° BA 158. Identical guns fire identical bullets horizontally at the same speed from the same height above level planes, one on the Earth and one on the Moon. Which of the following three statements is/are true? A) III only B) I and II only - 0-9 cose-adsint I. The horizontal distance traveled by the bullet is greater for the Moon. II. The flight time is less for the bullet on the Earth. III. The velocities of the bullets at impact are the same. I and III only II and III only 1.1 cos@=-035n9. tant = 1/3 C) D) E) I, II, III h-Vortat² xoxt-txt tu-Jite

求解

76. At time t= 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by -0.50t, in m/s² for t in seconds. At the end of 4.0 s it has traveled: 0 12 m 9=-052 = √²-025² C) 14 m D) 25 m E) 59 m E A) B) 77. The graph represents the straight line motion of a car. How far does the car travel between t = 2 seconds and t = 5 seconds? D v (m/s)

在講什麼😀

A rope of mass M and length L hangs vertically. What is the time I needed for a pulse to travel from the bottom end to the support? (A) 0.5 (L/g)0.5; (B) (L/g) 0.5; (C) 2 (L/g) 0.5; (D) 2 (L/g); (E) None. Which statement in want for the 66t 220

Vmax 那個是公市嗎 我有點忘記了

m kg/m or hom No s 141 Q & A 31 12 k = 100 N/m 2 3 e te he e m= 100 kg 43 14 1 + 3 her 手面上作R / F 15 I IE the t R = 10 cm Z s. H.M, AJ & it to rettan 2 2 2 7 16 5 2 z 11 7 ton time in 4 to 7 z 12 h 17 7 N.S? w/10 FOOOooooool P000000 * Font ki 支招 R R 结 1.5 B, olo k D. J.O (El lo Vmax? v=o m 了 字 说 平 We J? Vmax ZAR Vmay (T-16 ) > 7 = 了 J = mat J = m ( I max-o)

21題 教教我QAQ

Section 11.3 Angular Momentum J-s behind rmv a he ur 265 = ? a ter 30. Example 11.1: A 58.1 Iw COMP string and whirled at 18. Express the units of angular momentum (a) using only the funda- momentum of magr mental units kilogram, meter, and second; (b) in a form involving the circular path. Fir newtons; (c) in a form involving joules. marw horizontal and (b) the 19. Use data from Appendix E to make an order-of-magnitude esti- 31. Example 11.2. A stai mate for the angular momentum of our Solar System about the Max 27 the end of its lifetime galactic center. mu = 17.293 of radius 4.96 X 10' 20. A gymnast of rotational inertia 63 kg•m? is tumbling head over heels dwarf of radius 4.21 with angular momentum 460 kg•m?/s. What's her angular speed? 17.99 acted on the core, fine A 660-g hoop 95 cm in diameter is rotating at 170 rpm about its 32. Example 11.2: Astro 22. A 1.3-th-diameter golf ball has mass 45 g and is spinning at central axis. What's its angular momentum? L: 1W=0-66*(0-95) x 140x277.10 km and determin core that collapsed to 3000 rpm. Treating the golf ball as a uniform solid sphere, what's ing with a period of 4 its angular momentum? 18-3 33. Example 11.2. The s 10-598 rpm With her arms outstre Section 11.4 Conservation of Angular Momentum tational inertia is 3.5 23. A potter's wheel with rotational inertia 6.20 kg•m? is spinning (Fig. 11.6b), her rot freely at 20.0 rpm. The potter drops a 2.50-kg lump of clay onto her final spin rate? L = 6 2 x 2-1 = 12-99~13 - 2x2 22 13= 60.48)" x 2.5 W W = 2 . X z W = 20x2T 60 ²2.1 ~ 1 12.574