想問這兩題！ ⑴ DE有疑慮— D等加速度如果和速率不同方向就不會漸增 —E 做直線運動也有可能是在直線上改變速度大小（方向不變），也不一定會是等加速度吧？ ⑸BD有疑慮— B不知？可以依照拋體運動的方法判斷嗎（最高處V=0/a不=0）？—D 如果這個是正確的話那上方的D... 繼續閱讀

二、多重選擇題:每題5分,共25分 FOR CE) 下列關於運動的概念,哪些正確?(應選2項)」是派地 (A)一運動物體之速度改變,則速率必改變 (B)平均速度的量值小於等於平均速率 (等速運動一定是直線運動 (D)等加速運動速率一定漸增 (E)一物體若作直線運動,則其平均加速度一定等於瞬時加速度 我四台

想問摩擦起電 如果是金屬和非金屬 那麼是只有非金屬帶正或負電嗎？ 然後金屬還是電中性

1. 答案: 全 說明: 略 P 答案: BC 說明: (A)(B)(C) 、塑膠片摩擦後帶負電,再將硬幣放置於塑膠片上,可使硬幣「靜電感應」而 正負電荷分離。此時,硬幣靠近塑膠片的一端帶正電,另一端帶負電, 二、以手觸碰硬幣可作為接地,使硬幣遠離塑膠片那一端的負電荷消失。 三、以手觸碰後(接地後),以絕緣夾子將硬幣夾起,此時硬幣帶正電,而塑膠片 仍帶有負電。 四、若手不小心再次觸碰(再次接地)被夾起來的硬幣,則硬幣將恢復電中性。 AE

想要問為什麼百分率幾近相等， 同位素中子數平均就會等於原本溴的中子數45 （它怎麼能確定那兩個同位素的中子數一點是ㄧ大一小的44、46，而不是46、47之類的？）

溴的原子序為 35,已知溴存在兩個同位素,其百分率幾近相同,而溴的原 子量為 80,則溴的兩個同位素中的中子數分別為何?【94 學測】 (A) 43 和45 (R) 79和81 ) 42 和 44(R) 44 和 46(E) 45 和47。

想問右下角的n代表什麼（老師寫的） 如果是代表有幾個波鋒的話為什麼左下便條紙兩種方式的答案不一樣呢？

範例 03 連續週期波 某生觀測拉緊的水平細繩上行進波的傳播,發現繩上相距 1.5 cm 的甲、 乙兩點,其鉛直位移之和恆為零,而甲點鉛直位移隨時間/的變化如圖所 示。試問下列何者可能是此繩波的波速? (A) 12 cm/s (B/7.5cm/s (C)5.0cm/s (D)4.5cm/s (E) 3.0 cm/s 甲點鉛直位移朋友濃喔 維就在E Tree fizb2. → 1.3=115 t ANTOP Ja jadi 0.2 1. Sem V ww 安波(? 房油(部) 1.5=(8-1) 4 不一定 0.4 0.6 :: Vitap 0.8 1.5cm V (4) 1.0 tmp Yax 2:2.5人 1.5 24-1 x → x 1.5m ² ²2 7. A ②. 1.6cm. $ x 三 24-1 【105 學測】 8/60入 P. cn/s.new. 1.5= /(2n-1)-½>

先修物理 老師只講解了看這個力的角度 但是不知道下面的題目怎麼代進去算(*´°̥̥̥̥̥̥̥̥﹏°̥̥̥̥̥̥̥̥ )/

O N-my (T) 力的mon ma 範例 03 1. 如圖,質量m的小球以細線懸於公車的天花板 3 下,當公車以加速度a=-g前進時,試問當懸 線相對於火車靜止時 4 1 (1)細線與鉛垂線的夾角 (2)此時細繩的張力為 平衡 my (in) Dis : ma 造成品(不平衡入 ①. m來一起》 2: ED 力 F mg of Doing, T a (1) ma mm 力) U Ⓒ. mjekp - T + my (m²) = 0 112 p.

21題 教教我QAQ

Section 11.3 Angular Momentum J-s behind rmv a he ur 265 = ? a ter 30. Example 11.1: A 58.1 Iw COMP string and whirled at 18. Express the units of angular momentum (a) using only the funda- momentum of magr mental units kilogram, meter, and second; (b) in a form involving the circular path. Fir newtons; (c) in a form involving joules. marw horizontal and (b) the 19. Use data from Appendix E to make an order-of-magnitude esti- 31. Example 11.2. A stai mate for the angular momentum of our Solar System about the Max 27 the end of its lifetime galactic center. mu = 17.293 of radius 4.96 X 10' 20. A gymnast of rotational inertia 63 kg•m? is tumbling head over heels dwarf of radius 4.21 with angular momentum 460 kg•m?/s. What's her angular speed? 17.99 acted on the core, fine A 660-g hoop 95 cm in diameter is rotating at 170 rpm about its 32. Example 11.2: Astro 22. A 1.3-th-diameter golf ball has mass 45 g and is spinning at central axis. What's its angular momentum? L: 1W=0-66*(0-95) x 140x277.10 km and determin core that collapsed to 3000 rpm. Treating the golf ball as a uniform solid sphere, what's ing with a period of 4 its angular momentum? 18-3 33. Example 11.2. The s 10-598 rpm With her arms outstre Section 11.4 Conservation of Angular Momentum tational inertia is 3.5 23. A potter's wheel with rotational inertia 6.20 kg•m? is spinning (Fig. 11.6b), her rot freely at 20.0 rpm. The potter drops a 2.50-kg lump of clay onto her final spin rate? L = 6 2 x 2-1 = 12-99~13 - 2x2 22 13= 60.48)" x 2.5 W W = 2 . X z W = 20x2T 60 ²2.1 ~ 1 12.574

第21題 到底要怎麼寫ಥ_ಥ

Section 11.3 Angular Momentum J-s behind rmv a he ur 265 = ? a ter 30. Example 11.1: A 58.1 Iw COMP string and whirled at 18. Express the units of angular momentum (a) using only the funda- momentum of magr mental units kilogram, meter, and second; (b) in a form involving the circular path. Fir newtons; (c) in a form involving joules. marw horizontal and (b) the 19. Use data from Appendix E to make an order-of-magnitude esti- 31. Example 11.2. A stai mate for the angular momentum of our Solar System about the Max 27 the end of its lifetime galactic center. mu = 17.293 of radius 4.96 X 10' 20. A gymnast of rotational inertia 63 kg•m? is tumbling head over heels dwarf of radius 4.21 with angular momentum 460 kg•m?/s. What's her angular speed? 17.99 acted on the core, fine A 660-g hoop 95 cm in diameter is rotating at 170 rpm about its 32. Example 11.2: Astro 22. A 1.3-th-diameter golf ball has mass 45 g and is spinning at central axis. What's its angular momentum? L: 1W=0-66*(0-95) x 140x277.10 km and determin core that collapsed to 3000 rpm. Treating the golf ball as a uniform solid sphere, what's ing with a period of 4 its angular momentum? 18-3 33. Example 11.2. The s 10-598 rpm With her arms outstre Section 11.4 Conservation of Angular Momentum tational inertia is 3.5 23. A potter's wheel with rotational inertia 6.20 kg•m? is spinning (Fig. 11.6b), her rot freely at 20.0 rpm. The potter drops a 2.50-kg lump of clay onto her final spin rate? L = 6 2 x 2-1 = 12-99~13 - 2x2 22 13= 60.48)" x 2.5 W W = 2 . X z W = 20x2T 60 ²2.1 ~ 1 12.574