f(x) = axe³² +1]
f(x) = ax²+bx+c
= a (x²+ ==x)+(
= a (x² + 1/2 x + (12²)) + (-α;
= a/x + = =/ ) ² + 4ac-b²
20
-7) + ₂ [02/²2 - 0×]6 =
令f(x)=0
ax²+bx+c=0
x² + x + ² ² ² = -√² +2²³
49²
4a²
(x + 1)² = b³²-4ac
49²
b
V= (h₂ k) = (-5, 4ac-b³²)
|x=
49
=
這麼技巧的數字是怎麼出
來的,是怎麼被人發現的?
( ± √b²-4ac
20
-b1√b²-4ac
20
2
(49²
b²-4ac1
40