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化學 高中

類題1.1的E選項,想請問在容器內形成氣態溶液,兩種氣體的體積是會重疊嗎?答案寫氫氣和氧氣體積都是2L

氣糖粒于間的距離很天 ② 當容器的體積固定時 0 氣體的體積就是容器的體 故可以再充入其他氣血 ):與氣體的英耳數無關 2L。 電站 2氣體壓力計 THE 2 (AW(C)(E) 152 atm = 0.2 atm W Pan +600=P大氣,Pat +600=752(mmHg) Pt=152 mmHg W(C) 氫氣的壓力變大 760 不同無 a N 故O2、H的體積均為 Ms 焦點 道耳頓分壓定律 4 190 左端水銀面下降,右端水銀面 26 H.的莫耳數一 (A)Xn. (D) 高山的大氣壓力變小,故右端水銀會上升 上升,故水銀兩端的高度差會小於60cm。 端的水銀會下降 , 而氮氣 =15.2 cmHg,故氮氣端水銀面會 > Pm=152 mmHg = 低於真空端水銀面 15.2cm。 顆2.1 78 76 (1)1040 atm = 78 76 (2)2 -×1013 hPa=1040 hPa → 大氣 + 74 (cmHg) 2 2cmHg 理想氣體 (2)-73 152 76 492 1000 =78+74(cmHg) atm=2 atm =n×0.082x (27+273) 氣體 不同的 (B) Pite 46 40×32 , H、He的w,均相同,故兩者的 2 + 12 ( ätw) (C) M-M₁, x> (D) 密度d= 密度相同。 2 27 (E)P = P× Xin, = t 經典題5.1 ●(C) (A) 分子數: 文:氫氣 2+(1+3)=2(atm) ( 12 莫耳) >甲烷 ( 16莫耳) > 二氧化硫( 64莫耳) no 所以 二氧化硫 £80.0 1.0 (B)由PV=nRT,在同一容器內,V、T相同,故Px ,大者,分壓大⇨分壓:氫氣>甲烷> 。 率:氫氣>甲烷>二氧化硫。 (C)莫耳分率Xxn。所以,大者,X大⇨ 莫耳分 3 (2) PVRT 養 (D)由PV=nRT,當P、T相同時,Van。所以,n大 者,V大⇨體積:氫氣>甲烷>二氧化硫 共通的物性分子間引力很 不停運動 (1)可以無限可 (2) 氣體分子碰撞物體因而一 補充教材 各種氣體的化性:同溫壓下mol数相同體積相同 反應 比一劍耳數 4+1 108 0.8-24 依題意 6.故可以分壓代替 P=(0.8-2x)+(04-x)+2x=1 ⇨x=0.2 2x 所以,一氧化氮分壓為0.8-2x=0.8-2×02 =0.4 (atm) 經典題7.1 ● (A) nRT 混合前,NH3的壓力 P 6.80 17 ×0.082×( 2.00 =4.92(atm) C) 0 .5 (40-) 氣體 性質 氣體 性質 氫氣 H2 氯氣 Cl2 可燃,密度最小的氣體 黃綠色,漂白水味道 有毒性 氦氣 He 沸點最低,最難液化的氣體 , 臭氧 O3 mo 00 強烈臭味,有毒性,具漂白 力 氨NH, 刺激性臭味,有毒性 二氧化氮NO 紅棕色,有毒性 會面水壓限 範例1 氣體的性質 下列有關氣體性質的敘述,哪些正確? (A)在體積固定的6L容器內含有4g氧氣,若抽出2g氧氣後,則剩餘氧氣的體積為3L (B)氣體均沒有顏色 (C)氣體可高度壓縮 (D)氣體的密度並不固定,會隨容器的大小、氣體 的質量多寡而改變 (E)氮氣與氦氣可以任意比例均勻混合於同一容器內,形成溶液 N2 He不反應 CDE 計 解 'g' 類題 1.1 下列有關氣體一般性質的敘述,哪些正確? (A)氣體粒子間的平均距離較液體大 (B)氣體分子本身的體積遠小於其活動的空間 (C)鋼瓶中充 滿1mol氦氣後,無法再灌入其他氣體 (D)氣體可以無限地膨脹、擴散(E)體積固定的2L容 器含有1mol O,若再通入1mol Hz,則O2的體積為IL 。 ABDEL -21- H,也是2L

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英文 高中

想問第9題 dedicate為什麼用vpp

Angela Duckworth, an American scholar, gave a TED Talk in New York entitled "Grit: The Power of Passion and Perseverance." The ideas in her talk were later made into a book with the same title, 3. was published in 2016. 4. years earlier, Duckworth accepted a job as a mathematics teacher at a public school in New York. Her talk details how 5. the years, her students gradually taught her that to be successful, natural intelligence alone is not enough. One must also possess what is known 6. grit. Grit refers to consistent effort 7. by a strong determination to achieve a goal. Through detailed research, Duckworth discovered that people with high levels of grit remain highly motivated to achieve their goals 8.giving up on them. In other words, someone with true grit will see himself or herself getting closer to his or her goal day by day. Therefore, that person will always be able to keep himself or herself achieving that goal. 团 重 9. 10. Her book Duckworth's TED Talk and book have since inspired millions remained on The New York Times' bestseller list for almost half a year following its publication. (C) 1.(A) what (B) which (C) how (D) why (B) 2.(A) so (B) such alne (C) very (D) same (A) 3.(A) which (B) it (C) that U (D) and (D) 4.(A) Few (B) Little) (C) A little (D) A few (5.(A) with (B) around (C) until (D) over (C) 6. (A) by (B) for (C) as (D) to be (B) 7.(A) drives (A) 8. (A) instead of CB) (A) dedicate B 10. (A) in turn (C) on their way (B) driven (B) regardless of (B) dedicating (C) driving (D) to drive (C) except for (C) dedicated (D) in addition to (D) to dedicate (B) around the world 興 Ho (D) around the corner

已解決 回答數: 1
英文 高中

第九題不是主動嗎,為什麼是+ed

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已解決 回答數: 1
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