想問一下這個定滑輪的加速度怎麼求🤔️ （沒有給答案所以我不確定～～）

bm=bwerf Mg- Tema (M-m) 9 = (M+m) a M a. (M-my g } :D WtW

求助～～ 我不知道我的算式哪裡錯了😭😭

Eu = EM. - o tobx1oxloo = 1/30/6+ 40% 0 -xX 16000 c o.bly op $06.70*103610-10055.46.40'* oberford 3 of = ES 1²+1000= 1000 x * [ | 1 LEFT 1.600 4 loom. 2 =-200 Voz 400 O 9 a 9200) 更o- 馬上練習1| 厦,大宗空與 南部。 從比水平地面高100m的屋頂水平拋出一顆質量為600g的籃球,籃球初速率為10 m/s。 當籃球擊中地面前瞬間,測得速率為40 m/s,設重力加速度為10 m/s,則墜落過程中籃 地 球損耗的總力學能為多少? 一 (A) 80J (B)150J (C)220J (D) 300J (B) 680J。2001 (105指考,答對率14%) 15. Vx² V t2.a.s. 40² Vo²+2.10.100 > V = 700 Vo=20. 1600-2000 V . ,

21題 教教我QAQ

Section 11.3 Angular Momentum J-s behind rmv a he ur 265 = ? a ter 30. Example 11.1: A 58.1 Iw COMP string and whirled at 18. Express the units of angular momentum (a) using only the funda- momentum of magr mental units kilogram, meter, and second; (b) in a form involving the circular path. Fir newtons; (c) in a form involving joules. marw horizontal and (b) the 19. Use data from Appendix E to make an order-of-magnitude esti- 31. Example 11.2. A stai mate for the angular momentum of our Solar System about the Max 27 the end of its lifetime galactic center. mu = 17.293 of radius 4.96 X 10' 20. A gymnast of rotational inertia 63 kg•m? is tumbling head over heels dwarf of radius 4.21 with angular momentum 460 kg•m?/s. What's her angular speed? 17.99 acted on the core, fine A 660-g hoop 95 cm in diameter is rotating at 170 rpm about its 32. Example 11.2: Astro 22. A 1.3-th-diameter golf ball has mass 45 g and is spinning at central axis. What's its angular momentum? L: 1W=0-66*(0-95) x 140x277.10 km and determin core that collapsed to 3000 rpm. Treating the golf ball as a uniform solid sphere, what's ing with a period of 4 its angular momentum? 18-3 33. Example 11.2. The s 10-598 rpm With her arms outstre Section 11.4 Conservation of Angular Momentum tational inertia is 3.5 23. A potter's wheel with rotational inertia 6.20 kg•m? is spinning (Fig. 11.6b), her rot freely at 20.0 rpm. The potter drops a 2.50-kg lump of clay onto her final spin rate? L = 6 2 x 2-1 = 12-99~13 - 2x2 22 13= 60.48)" x 2.5 W W = 2 . X z W = 20x2T 60 ²2.1 ~ 1 12.574

第21題 到底要怎麼寫ಥ_ಥ

Section 11.3 Angular Momentum J-s behind rmv a he ur 265 = ? a ter 30. Example 11.1: A 58.1 Iw COMP string and whirled at 18. Express the units of angular momentum (a) using only the funda- momentum of magr mental units kilogram, meter, and second; (b) in a form involving the circular path. Fir newtons; (c) in a form involving joules. marw horizontal and (b) the 19. Use data from Appendix E to make an order-of-magnitude esti- 31. Example 11.2. A stai mate for the angular momentum of our Solar System about the Max 27 the end of its lifetime galactic center. mu = 17.293 of radius 4.96 X 10' 20. A gymnast of rotational inertia 63 kg•m? is tumbling head over heels dwarf of radius 4.21 with angular momentum 460 kg•m?/s. What's her angular speed? 17.99 acted on the core, fine A 660-g hoop 95 cm in diameter is rotating at 170 rpm about its 32. Example 11.2: Astro 22. A 1.3-th-diameter golf ball has mass 45 g and is spinning at central axis. What's its angular momentum? L: 1W=0-66*(0-95) x 140x277.10 km and determin core that collapsed to 3000 rpm. Treating the golf ball as a uniform solid sphere, what's ing with a period of 4 its angular momentum? 18-3 33. Example 11.2. The s 10-598 rpm With her arms outstre Section 11.4 Conservation of Angular Momentum tational inertia is 3.5 23. A potter's wheel with rotational inertia 6.20 kg•m? is spinning (Fig. 11.6b), her rot freely at 20.0 rpm. The potter drops a 2.50-kg lump of clay onto her final spin rate? L = 6 2 x 2-1 = 12-99~13 - 2x2 22 13= 60.48)" x 2.5 W W = 2 . X z W = 20x2T 60 ²2.1 ~ 1 12.574

［高二物理 圓周運動］ 請問這一題的E選項該怎麼解釋？ 感謝你們

度運動 定是圓形 F=mv² T. For mor > (BK)2. 設地球為正球體,半徑為R,自轉週期為T,則下列敘述哪些正確? (A)在臺灣與在美國的時間不同,所以轉動的角速度也不同 (B)若有一質量m的物體置於赤道上,則 重量減輕 4元 mR (C在緯度為6的地 方,其向心加速度為4rfR 向為 33ton FC=0 TA COS (D在北極的向心力與重力之比值為0 (因 E. m 6 cos 元 Y. T2 為北極與 赤道距地心的距離一樣,所以視重皆相同

不好意思，大家可以幫我看一下這一題嗎？ 答案是5.4

Ti mi 40. 如右圖,mi = 2Kg,mp = 3Kg,各接觸面之靜摩擦係數皆為 0.6,則系統不滑動,若m、mi、M均不動,求M之最大 是 值為 Kg。(不計繩重,滑輪重,且滑輪無摩擦力) PETELLEN E <) O T1 m2 M

想問一下各位大大這題要怎麼解釋呢？

x 11x1x1x Ē X 25. 銅片置於水平桌面上自南 向北通有電流I,若於此空間中有 鉛直向下之均強磁場B,今以微伏特計測量垂直於電流之東 西兩端電位差將測得X,Y兩端何者電位較高,飞?, 由此可發現金屬導線上可移動者為帶負電之粒子。 【此實驗稱為霍耳效應(Hall Effect)) X X X X X x|xx. xxlxx 10 X X X X X T X

求解這樣算是對的嘛？ 想問第二小題

星球 Rf379>地 R# 日 9. 已知地球繞日的半徑為R、地球繞日公轉週期為1年;若自地球表面 測得某星球與地球連線和地日連線之最大夾角為37°,設兩者軌道均 為圓形,如圖所示,則: (1)該星球繞日軌道半徑為何?(5分) (2) 該星球繞日週期為多少年?(7分) 答:1) Limg]*> 5m 3.Ro Rit ZY 了 Re: (2) T= Z2 So on ar 「e 15日 了 Tito Tz 片,

（1）bc (2)ad 求詳解🙏謝謝 有沒有除了我寫的其他種算法

ERP (D) | KR² 範例4 質量為m的物體接於一彈簧,在光滑水平桌面作 SHM時,最大速率為p,振幅為R, 彈簧力常數為k。當物體動能與彈性位能之比為1:3時,回答下列問題: (C) 4m 2 4 IER? w * 2m (1)此時物體速率可表示為下列何者?(應選2項) (A) (B) IC | my ? m 3my? 4k (B (B) 4k (2) 此時物體距平衡點之距離可表示成下列何者?(應選2項) my² (C) ( (D) R ® RF 10 ) k 解答 CHCE = 1 mv, + 1 X ² = mv ' _ I kx² = 1 kk² SEk I'm Vx 1 -- het Ikx² I'm Vx + 3 + 3 mx? + 3 mx = 2mVx = 2 mV = 1/R² \ KR² Vx= 14m

(7)的張力比怎麼算，我已經忘記張力怎麼算了，詳解寫的也不懂為什麼

( f=5 A: 1 a = 4 TL²Rf² - 4 2 ² + 1 + 25 100 T² nefer 6 圓周運動物理量 1 -- 0 C C A LA B m - 二 m 如右圖所示,A、B、C三質點均繞圓心O作等速圓周運動, ma = 2 m' mg = 2 m' mc = m' I. OA = AB = BC, a: (1) A、B、C三質點旋轉的半徑比? (2) A、B、C三質點旋轉的周期比? (3) A、B、C三質點旋轉的角速率比? 4 的 (5) A、B、C三質點旋轉的向心加速度比? (6) A、B、C三質點旋轉的向心力比? (7) 繩子 OA 張力:AB 張力:BC 張力為? 答 01:2: 节 12) 1 = 1)