想問這題🙏 空間中的平面與直線 克拉瑪

二 ax + cy + bz = a + 2bc 9.597 cx + by + az = b2+ 2ca (ab CHE FETE) 52 (、c為互異正數 br + ay + cz = c2+ 2ab

想請問這題🙏

+ O [82 151 1 ] 下列各選項中的函數,請選出其振幅與週期相同的選項。(多選) (1) fi(x)=r sin 2x + 1 cos 2x (2) f(x)=2 sin ax+2 cos ax (3) f} (x)=12 a sin x+12 a cos x (4) fe(x) =- ) 10 2 V2 2 1 1 sin 2x+ cos 2x ✓2 (5) f(x)=- √2 m sin Ax+ IT X COS A’x IT IT 解題關鍵 11. 遇到asin 9+bcos 4→先疊合就對了。 2013 2. y=a sin(bx+c)+d的振幅為「a」,週期為 2 161 ar sina eshte Ar +45 or Y+45 Sin (BL Xt

這題我算出兩個答案覺得怪怪的😥 是對的嗎

- - 8. FEZ POSTITATU E1 : 5x – 2y + 4z = 1 E 2 ax + by + cz = 6 ETTE | DF-1 | 2/5 2 離為 br=2 trt=2 (a,b,c)=(10,4,8), 15 6r=3 -brell (70, 12-24) 2 rid -

積分

0 x+x=>x=0 = X(X+>) (XL)=0 =) X=-2, or 0-17 + + E +1) +- 8 nanti) (INT) 6 ) 轰轰5 試求 it.no Chicht) (二基礎題:每題1分,共63 分 1. 函数f(x)=x的圖形與直線x=0,c=2及x軸所圍成的區域面積呎,若將 (10,2) SEE n 5 ) ## 0=xo <x1<x2** <x=2 ( xi-1, xi] +32 t;=x; i=1, 2, .,n:*: (1) 黎曼和(a) • Are 3. 下列各積分值: (1) 1(32+1-1) de (2) / (4-28+7) de (3) | ((x+3)(x+2)/dt (2) R. 配合課本例题。 i=1 6 0章- 6. 如右 域面 ( fct1= € = 21 Efter ha fet ist. ** tn) = Efter - 言十六 动动 - 1 (tittas menti) (2h) nchti) (2011) entlanti) fon zr (

幫解(a)(b)(c)(d)

1. A periodic signal x[n] is shown below. x(n] th 0 2 11 4 5 8 It's Fourier series representation is as follows: x[n] avejkuyn k=<N> (a) Determine the fundamental period N of the periodic signal x[n]. (b) Determine the fundamental frequency wo. (c) Plot the real part of ejern (denoted by Re{ejun}). (hint: eje = cose + jsin) , Refeiwn} →n (d) Plot Re{ej2wyn} • Referawang →n 3 5 2

求救第55題 完全看不懂他要我幹嘛

Year slenue Req) = 1932 1958 +1000 q R 9)=-1000q =74 1963 1968 COM If the price in dollars of a stereo system is given by 1000 p(q) + 1000, 1000 ² q where q represents the demand for the product, find the mar- ginal revenue when the demand is 10. 54. Profit Suppose that for the situation in Exercise 53 the cost in dollars of producing a stereo systems is given by C(q) = 0.2q2 + 69 + 50. Find the marginal profit when the demand is 10. 59. Marginal Product of Labor The output y of a manufacturing y process is a function of the size of the labor force n using the function 1990 +1000 1971 1974 = 990 197 197 19 19 1 y = kVn. The marginal product of labor, defined as dy/dn, measures the rate that output increases with the size of the labor force, and is a measure of labor productivity. (a) Show that (c) Using the a cubic f respond the rate and 200 (d) Discus descri part ( the y (e) Exp data calc ful x C(x) = 58. Money 1955-7 dy k dn an (b) How can you tell from your answer to part (a) that as the size of the labor force increases, the marginal product of labor gets smaller? This is a phenomenon known as the law of diminishing returns, discussed more in the next chapter. 56. Profit An analyst has found that a company's costs and rev- enues in dollars for a product are given by x2 C and R(x) 2x 2 5000' respectively, where x is the number of items produced. (a) Find the marginal cost function. (b) Find the marginal revenue function. (c) Using the fact that profit is the difference between revenue and costs, find the marginal profit function. (d) What value of x makes the marginal profit equal O? (e) Find the profit when the marginal profit is 0. (As we shall see in the next chapter, this process is used to find marimum profit.) A wher in bi find year (a) (C) (e) nad since

請問這一題 怎麼算 謝謝🙏🥺

3 利用數學歸納法證明:17+37+5 +…+(2n-1)} = n ( 2n-1) 2n+1), 對 所有的自然數n 恆成立, FERR H

求解c選項錯誤的原因

1 (B)L是平面上的直線, L, 是平面E 上的直線,若EFE.,則 LL, (C)設一直線交一平面E於A點,若在E上過4點有一直線L與L垂直,則L垂直平面E於4點 (D)已知相異二平面E、F交於一直線L,若L垂直另一平面G,則E、F均垂直平面G (E)若L、L,為一組歪斜線, L. 、 L. 也為一組歪斜線,則L、L 亦為一組歪斜線。 答: 12 你向众

要如何解1,2

1 .: MAC T=1X(r-6) 0得r=) 10)即為反射點坐標 如上圖,若直線L與AB 相交 則 r>1或P<-6 ..AC 範例 16 5 2 ..map- - . m A(2,8) B (6,4) 2 1). Imag 5 - B°(6-4) - AD TSFEITA 5x+2y=0 (1 設 D(x,y)其中x<0,y>0 - AD=AB=7 (5-0)2+(2-0)2 = 29 (r-0)2+(y-0)2 = 29 D) x+y+=29. (2) 解1、2得x=-2,y=5 ..D(-2,5) s出發到B6,-4) 12 3 2. -2+5 5+2 9 中心O為 BD 的中點 0 2. 2 3 7. 9 5 2 2

想知道為什麼是這個答案，求詳解！！ 這是資訊～～

OFE (D) UDI 00 (D 它 後, [5] = 1,2,3,4,518 - 9. 執行下列 C/C++ 程式片段後,輸出結果為何? [ int a[5] = {1, 2, 3, 4, 5}} , | for (i = 1; i < 3; i++) TE cout << a[i]; (A) 12 (B) 23 (C) 123 (D) 234 ((B() (