4
1 2 8. 設方程組
a₁
b₁
(1)
≠0
a₂ b₂
a1 C1
a1 b₁
5
(2)
=8
ax+by c₁
之解(x,y)=(-3,8),請選出必定正確的選項。(多選)
ax+b₂y=c₂
(4) a₁ (-sy) + b₁ (4x) = -3 C₁
a. ( + y) + b, (= ± x ) = C₁
· x)
+4=-3x=8 → X=-6, Y = = = =
q
b -5
85
C₂
a2 b₂
(5)
b₁
(3)
b₂
55
a1 b₁
=
3
C₂
az bz
4bx-5a₁y+3c₁ =0
(4)方程組
之解(x,y)=(-6.
9
4b2x-5ay+3c2=0
5
(ax+by+cz=0
(5)方程組
之解(x,y,z)=(-3t,8t,t),其中¢ER
@2x+by+c₂z=0
Ko
12, CT (4)
b₁ C₁
1 = 20
b₁ Cz
8
1a, bi
Ax = 45
-C2-02
X = 15 × (3) ₤-6
1x(-3)=-6
-204