参考概略です
A(1+2i),B(3),C(7+8i)
{(7+8i)-(1+2i)}/{(3)-(1+2i)}
=3i
=3{cos(π/2)+isin(π/2)}
∠BAC=π/2
補足計算
{(7+8i)-(1+2i)}/{(3)-(1+2i)}
={6(1+i)}/{2(1-i)}
={3(1+i)}/{(1-i)}
={3(1+i)(1+i)}/{(1-i)(1+i)}
={3(2i)}/{2}
=3i
参考概略です
A(1+2i),B(3),C(7+8i)
{(7+8i)-(1+2i)}/{(3)-(1+2i)}
=3i
=3{cos(π/2)+isin(π/2)}
∠BAC=π/2
補足計算
{(7+8i)-(1+2i)}/{(3)-(1+2i)}
={6(1+i)}/{2(1-i)}
={3(1+i)}/{(1-i)}
={3(1+i)(1+i)}/{(1-i)(1+i)}
={3(2i)}/{2}
=3i
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