(3) Ž (3k-()²
kol
3
67 962-61+1 = 9. n (n+1) (24+1) f. h(4+1) +h
=
=
f 2
2
3n (n+1) (2n+1) - bn (n+1)+2n
2
n{3(n+1)(2n+1)−6(n+1)+2 }
64²+94+32
4 {3 (2n²+ 3n+1)-64-6+23
2
n { bu² + 3n-1]
55 (1.42 (1) (261) 222
=
K=1
=2.
2
3
th
flant
「違い
Zn (n+1)(2n+1)