✨ 最佳解答 ✨ qn 10個月以前 想法一:當成直線,考慮斜率 OA 斜率為 1 OB 斜率為 -3/2 以差角公式計算 [ (-3/2) - 1 ]/[ 1 + (-3/2)·1 ] = [ -5/2 ]/[ -1/2 ] = 5 想法二:找三角形關係 tan∠OAB = 1 tan∠OBA = 3/2 tan∠AOB = tan(180° - ∠OAB - ∠OBA) = - tan(∠OAB + ∠OBA) = - [ 1 + 3/2 ]/[ 1 - 1·(3/2) ] = - [ 5/2 ]/[ -1/2 ] = 5 留言