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解答

f(0)=2 f(2)=3 f(3)=-1 deg f(x)=2
f(x)=ax(x-2)+bx+2
代入x=2及3
f(2)=2b+2=3 b=1/2
f(3)=3a+3b+2=-1 a=-3/2
f(x)=-3/2x(x-2)+1/2x+2
=-3/2x²+7/2x+2
配方
=-3/2(x-7/6)²+....

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