Question

登愣愣

想問問這題 謝謝！

35
1、若tan=cos日,求1
+
1
1-sine 1+sine
的值=
√5+
1+1
1-Gin
tan

Answer 1

綾

tanθ = sinθ/cosθ = cosθ
=> sinθ = (cosθ)^2

(sinθ)^2 + (cosθ)^2
= [(cosθ)^2]^2 + (cosθ)^2
= 1

[(cosθ)^2]^2 + (cosθ)^2 - 1 = 0
=> (cosθ)^2 = (-1 ± 5^0.5)/2 (-不合)

所求
= [(1 + sinθ) + (1 - sinθ）] / [1 - (sinθ)^2]
= 2 / (cosθ)^2
= 4 /(-1 + 5^0.5)
= 1 + 5^0.5