解答

3sin(2x+2π)+4=5/2 (π≤x≤2π)
3sin(2x)=-3/2
sin(2x)=-1/2

(2π≤2x≤4π)
2x=(7π/6 +2π) or (11π/6 +2π)
2x=19π/6 or 23π/6
x=19π/12 or 23π/12

19π/12 + 23π/12
= 42π/12
= 7π/2

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