f(x)=(x^2-1)Q(x)+(5x-11)
=(x+1)(x-1)Q(x)+(5x-11).....f(1)=-6
f(-1)=-16
f(x)=(x-3)(x-2)Q’(x)+(-2x-6)
......f(3)=-12
.......f(2)=-10
f(x)3次 令f(x)=a(x-1)(x+1)(x-3)+b(x-1)(x+1)+c(x-1)+d
f(1)=-6=d
f(-1)=-2c+d-16.....-2c=22 c=-11
f(3)=8b+2c+d=-12 8b=-12+28=16 b=2
f(2)=-10=-3a+6-11-6
3a=-1 a=-1/3
f(x)=-1/3(x-1)(x+1)(x-3)+2(x-1)(x+1)-11(x-1)-6
如果題目沒有要乘開這樣就好