5. 如右圖,AB = AC = 13, BC = 10,
-
G為重心,則GD =
-
J41
B
2
B
1360
B
>
6
15
3
-
二
M.
118
6o= x (x 3618
10x1)
stato
603
lo
ta
6. 如右圖,直角AABC 中,G為重心,
M為斜邊中點,若AC = 18, BC =
30
24,則GM-
36
中
216= 1 / 2 x tt 26
*x
316
96
(432
18
366=216
3 076
X 18
076
5-6
9
J
O
(5
-
3
24
3
X
4
cor
B
6
24
3
2
>
4d
too
07 6 144
2
+324
14
(>