解答

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For your reference

仲遠

The solution of 1+2+3 +4+...+n ≥200 is n ≥19.05... .
You should write 1+2+3 +4+...+n ≤ 200 so that the maximin positive integer solution of n is 19.

仲遠

*maximum

Call me Bravo

hi, handsome guy, I got your kindness and thx. The n=19 or n=20 is a number just only for easy to count.

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