あ 8個月以前 (a+b-c+d)(a-b+c-d) ={a+(b-c+d)}{a-(b-c+d)} =a²-(b-c+d)² =a²-(b²+c²+d²-2bc+2bd-2cd) =a²-b²-c²-d²+2bc-2bd+2cd 留言