Question

朝比奈まふゆ

求解這題

4. =Rƒ (x) = ax² + bx + c ƒ (1) = −2, f'(1)=-1, f'(2)=3,
確?
(1) a=2
(2) b=-4
(3) c=3
(4) a+b+c<0
(5)f(3)=4.

Answer 1

✨ 最佳解答 ✨

綾

f(1) = a + b + c = -2
f(-1) = 2a + b = -1
f(2) = 4a + b = 3

f(2) - f(-1) = 2a = 4
a = 2
b = -5
c = 1

f(3) = 9a + 3b + c = 18 - 15 + 1 = 4