Question

lin

想請問這題

ax2-x+1-a
9. 設 f(x)=
x=1
x-1
"
若f(x)在x=1處可微分,則a=
51,
x=1

Answer 1

✨ 最佳解答 ✨

qn

lim_{x→1} (ax²-x+1-a)/(x-1) = 51
lim_{x→1} [a(x²-1)-(x-1)]/(x-1) = 51
lim_{x→1} [a(x+1)(x-1)-(x-1)]/(x-1) = 51
lim_{x→1} [a(x+1)-1] = 51
2a-1 = 51
a=26