as =
1x1x2x 9
11、試用數學歸納法證明:∀n∈N,1.3+2.4+3.5+..+n(n+2)=z(n+1)(2n+7)。
1/6/1=1 = 1x₂ = + + P²+2x9:/= to XII
131
7270
√/2n=1<=) 1×3 +2×4 + 3x5 +₁.₁+k(K+2) = = K (K+1)(2k+7)
3₁) n=k+1 2 1 x 3 + 2 x 4 + 3 + 5 +...+ kek+i) (k+i) (k+3) = (K+1) (2K+ 1) + (K+1) (K+3)
1+NAVY+KANN.
lig
12.設n∈N,求證10″ +3.4"+5為9的倍數。
Wh22 A(n)=22-
3n+1 12₁,52n+1
她
2K+5+6K+0) 2
=(k+1) [ 4²+7K+6k+¹8ngs
6
125 (K+1) | 2K²+13k+1₂T (K+²)(2K+9)
6
(二) + (K+1)(K+1+1)(2k+2+1)
优n2並試服之
個三倍數救险
la
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