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請問這題謝謝！（附答案）

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Example 3
Find y' if sin(x + y) = y² cos x.
Solution :
Differentiating implicitly with respect to x and remembering that y is a function
of x, we get
y'
日日
cos(x + y) (1 + y) = y²(- sin x) + (cos x) (2yy')
(Note that we have used the Chain Rule on the left side and the Product Rule
and Chain Rule on the right side.) If we collect the terms that involve y', we get
cos(x + y) + y² sin x = (2y cos x)y' - cos(x + y) · y'
y² sin x + cos(x + y)
2y cos x cos(x + y)
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Answer 1

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就照隱微分的做法做，你有特別想問哪部分ㄇ（？