56. f(x)= a(x - 1)(x - 2)+b(x - 2)(x – 3)+c(x-3)(x-1) · g(x) = 3x+1 + f(0) = g(0)
f(-1)=g(-1) · f(5)=g(5) "**+(a,b,c) = LSI;
Ans: (527)
f(x) = ax 3x+2)+b (x x x +b) tc ( rzuch the
2 tú
(5,2,-
19tb to) x + (-39-36-42) 2 (A za abb+ z oo
parblo+36-1-0 3 4 5 1 2 3 4 2 0 0 4
一 3a 3b-4cy-b) 2 + 2C 200 og 6 +6 = 30 as
57. 設f(x)為一多項式,若(x+1) (x)除以x+x+1的餘式為5.x +3,求(x)除以x+x+1的
(teng - () f () 14 ? + +1 , f () ** +x+
餘式為
b = zato
at btc -o o
x6 = 4
4b+c=16
-= 44223
2.1
50
azza 22=0
Ans: 2x+5
-
58. 16x4 -8x? – 28x? +36x-5= a(2x-1)* +b(2x - 1)' +c(2x - 1)2 + d(2x-1)+e : :
(1)數對(a,b,c,d,e) =.
(2)以(2x-1) 除(r)之餘式為。
射後第二位(以下四捨五入)為
7.
