Question

嘻嘻嘻嘻

怎麼看答案有兩個或一個呢

wa Fort
B)
[練4
“十
[練1]
x+2y = ax
方程組
16x + 2 y = ay
有異於(0, 0)的解,則實數a=[Zerl]
f
(1-9)x+ 2y =0
[ 6 xH(2-a)y=0
G - 2
1 -
2.
-za-a--sa
2-a
a=200 lt
Tr. Fu
有異於x = 0, y = 0 以外的解,試求實數k的值()
3x + ky = 4y
- (1-4) (2-6) - 12 20
( kx + 5) = 2x4-24th - 1220
[練2]
若方程組
k²-66-7
(K-2)* + 5y zo
+
3x +(K-4) y = 0
k – 7
k tl
ktk = ble
K-2
3
20
K= 7or-l
J
12
K-4
(K-2) (K-4)-18=0
→ 1²-4k-2k+8 -15 28.9