to be lim ant x.
4X-2 )
An (3 bn. 4) = -bn-
-bn-2
3bn-y
)
3x+1
|
| =
(a=0
(2)設數列{an}的遞迴關係式。
* liman
a,
1+ Co.,
3- 0,-1
n22'
[
03-5, as te, aj, a 5,0-55
no ]
ht |
Hak
3-ako
a = √ 3-ky
0 n. 10% a = t1 =0/0
WA ana na ta @ te na kat ako te ll 3 2
to be a base de an = 1
外有自然数n面八方
DJ te n-krip}
akty -
Ter 2) į A-
*]
例 6. 數列<a >={
A |
An+1 = 12+ a,,nz
(1)已知這數列
收斂,求其極限 (2)若未知是否收斂時,如何證明其為收
效?
Ai=52
= zran
11) e a lim an= lim ant) =X
han hantara lansa)
( cançanti)
e lim Anel = lim (2+0n
Y、础久)
17).
Ant
hao
hod
hop
hao
| |_
ON
X= (2+1
x= x-2=0
x=2007 (426)
X2
1-1-11
