Question

はる

偏導関数を求める問題で6番が分かりません。
fxの求め方はどこが間違っているのでしょうか？

次の関数の偏導関数を求めよ
(14 — 1) f(x, y) = x² + 5xy-y³
(14-3) f(x, y, w)
(14-5) f(x, y, w)
= 2w² +8wxy - x² + y²
= 6w³ + 4wx + 3x² - 7xy
1
uvw
(149) z = f(a, b) = (a + b)²(a - b)
a² + b² + c²
a+b+c
(14-7) f(u, v, w) =
(1411) y = f(a,b,c) =
(14-13) p = f(x, y, z)
(1419) z =
=x5yz + xy5z + xyz5 + 1
(14-15) s = f(p, q,r) = (p+q+r)4
3
(14-17) z = x² + 2x²y + xy² + y²
+ 3xy
(14-21) z =
ab + bc + ca
abc
x² - y²
xy
(141) fx = 2x + 5y
5y
(14-2) fx=(x + y)²
(14-3) fx = 8wy - 2x
-y-w
x²
fy = 5x - 3y²
5x
(x + y)²
fy=8wx + 3y²
fy
3.3 偏微分
==
fy
x
3y²
(14-4) fx ---
fy
3y
(14-5) fx = 4w + 6x - 7y fy=-7x
(14-6) f
x
fw = 1 /
X
(14-2) f(x, y) =
(14-4) f(x, y) =
x+y+w
(14-6) f(x, y, w) =
x
(14-8) z = x²y² + 2xy - x²y - xy² + 4x
+ 4y + 4
(1410) s = f(p,q,r) = pqr(p + q + r)
b+c
a+b
(1412) s = f(a,b,c) =
pq + qr+rp
pqr
2x - 3y
x + y
x+y
3y
(14-14) s = f(p,q,r) =
(14-16) s= (p+q+r)(p-q-r)
(1418) z = (a + 2b + 3c)5
(14-20) z =
(14-22) z =
fw = 18w² + 4x
ab + bc + ca
a+b+c
abc
ab + bc + ca
fw = 4w + 8xy
(x + y ) x (39) ¹-
かけてる
3g
17--5 XF="HE
MA
22

f(x, y, w). I+ZIW
= (x + 2 +W) (x)'
fx=1.-12²= |--|--
fr - 1. x² ==
fy =
x²
X²
K²
fw= 1. (2) ² = =

Answer 1

✨ คำตอบที่ดีที่สุด ✨

えだまめ🫛

f(x,y,w) = (x+y+w)/x = 1 + (y+w)/x

fx = -(y+w)/x²
fy = 1/x
fw = 1/x

こうです🫛

はる

ありがとうございます☺️