Question

Kiera❤

請問13題 為什麼log-alpha+log-beta=-log6

13. (log 2x) (log 3x)=1
⇒(log x+log 2) (log x+log 3)=1
⇒(log x)²+(log 2+log 3) log x+(log 2) (log 3)-1=0,
令=logx,則loga, log B為
2+(log6)+(log2)(log3)-1=0的兩根,
loga +log ẞ=-log 6 E loga ẞ=log-
6
18.如圖

10x + 10 = 2.10"
2+2
(10)2-200.102+10
(10-100)* -0.
10=100-102
1)若方程式(log2x)(log3x)=1之兩根為a,B,則aß=
<2>(loga
(loga + logx) (loga+logx) =|
(x + (lez+3)||x+(10), (boys)-1=
++ logbt + (bgz) (logs) - 0