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自然 國中

求2(4)、4(全部)(想知道公式推理🙏

(一)(1)三種情形中溫度最高的是何者?(A)甲(B)乙 (C)丙 (A) 20 (B) 54 (C) 18 (D)62 )(3)若將此溫度計之玻璃管更換成較細的玻璃管,則甲情形中水面高度變化為 何? (A)增長 (B)縮短 (C)不變 2. 如附圖所示,將均為 20 克、25℃之金、銅、鋁三球,置於正在加熱的水中,經一段時 間後,溫度停留在 100°C。已知金、銅、鋁比熱分別為0.031、0.092、0.211 卡/克-C, 試回答下列問題: VIII -溫度計 ( )(1)三金屬球放入熱水時,哪一球溫度上升最快? (A)鋁 (B)銅 (C)金 ( )(2)最後比較此三球之溫度何者最高? (A)金 (B)銅 (C)鋁 (D)三球相等 )(3)三球中何者吸收熱量最多? (A)鋁 (B)銅 (C)金 (D)一樣多 ( (4)自熱水中取出三球,分別置入三個裝有等質量20℃水的相同塑膠杯中(設熱 量無損失),則裝入何球之水溫最低? (A)鋁 (B)銅 (C)金 (D)一樣多 50x72 18 3. 104℉時食鹽的溶解度為 36 g/100g 水。甲杯:在 50 g、104°F的水中放入食鹽 20 g 並均 勻攪拌;乙杯:在 50 g、104°F的水,使用熱量均勻之酒精燈加熱 10 分鐘後,水溫變 為176°F,此時投入 20g 的食鹽並均勻攪拌。水之比熱為1卡/克-C。試回答下列問題: B)(1)酒精燈每分鐘可產生幾卡的熱量?(A)200 (B)360 (C)2000 (D) 3600 (十)(2)甲杯之重量百分濃度約為多少? (A)26% (B)28% (C)34% (D) 36% ( )(3)若想將甲杯食鹽水中的食鹽完全析出,需使用何種方法? (A)溶解法 (B) 結晶法 (C)排水法 (D)過濾法 10,26 19 列何者?(A) 溫度 41= mix: 07. DHE sist 將初溫 20℃,質量均為 20 g 的 A、B、C 三金屬塊,置入沸水中,達熱平衡後取出, 分別放入裝有 50g、20°C水的甲、乙、丙三個絕熱燒杯中,經數分鐘達熱平衡後,甲、 乙、丙三杯水的溫度分別是30℃、26℃、22℃,試回答下列問題: (A)(1)A、B、C三金屬分置於50g、20°C的冷水中,達熱平衡時,金屬塊的放熱情 況,大小關係為何?(A)A>B>C(B)B>C>A(C)C>B>A(D)C>A>B (A)(2) 三金屬在沸水中所吸收熱量的大小關係為何?(A)A>B>C (B)B>C> A (C)C>B>A_(D)A=B=C (C)(3)A、B、C三金屬塊在沸水中受熱到達熱平衡這一段的時間和溫度關係圖為下 AB B B Vc 時間 (B) 溫度 時間 溫度 (C) 時間 (D) 3490 A 68 時間

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英文 國中

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