Question

巧克力螺旋麵包

求解🙏🏻🙏🏻

(3) α, +p+c,-3apc=(a+p+c)(a,+P+c-ap-pc-ca)
2.(能力指標:a+b+c*−3abc的應用) D=
a+b+c=5, ab+bc+ ac=3 ta³+b³ + c³-3abc = ?
,
(x)-(p)+(p-c), +(6-0), 50
777

Answer 1

✨ 最佳解答 ✨

qn

a³+b³+c³-3abc
= (a+b+c)(a²+b²+c²-ab-bc-ac)
= (a+b+c)[(a+b+c)²-3(ab+bc+ac)]
= 5 [ 5² - 3·3 ]
= 5 · 16
= 80