Question

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想請問這一題如何計算，謝謝🙏🏻

2.
f(x) = 4xf fix) dx + 3x + 1
Solve f(x)=

Answer 1

✨ 最佳解答 ✨

qn

設 ∫₀¹f(x)dx=k (k是常數)
f(x)=(4k+3)x+1
代回積分
∫₀¹ (4k+3)x +1 dx=k
[(4k+3)/2 x² + x]₀¹=k
(4k+3)/2 + 1 = k
k=-5/2
f(x)=-7x+1

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感謝您
🙏🏻