解答

✨ 最佳解答 ✨

1.
假設價格書寫為 xy 元
實際數字應寫成 (10x + y) 元
看錯的價格為 (10y + x) 元
則 (10y + x) - (10x + y) = 18
-9x + 9y = 18
-x + y = 2 => x = y - 2
若 x = 7 則 y = 7 + 2 = 9
若 x = 8 則 y = 8 + 2 = 10(只能擺一個數字,故不合)
=> 真實價格為 79 元
買兩個可減 5 元 = 79 * 2 - 5 = 153 元

2.
依題意:
(甲 - 8) = (2/3 乙) = (4/5 丙) = (8 + 1/3 乙 + 1/5 丙)

取 (2/3 乙) = (8 + 1/3 乙 + 1/5 丙)...(1)

(4/5 丙) = (8 + 1/3 乙 + 1/5 丙)...(2)

(1):
1/3 乙 = 1/5 丙 + 8
=> 5 乙 = 3 丙 + 120
=> 5 乙 - 3 丙 = 120...(3)

(2)
-1/3 乙 + 3/5 丙 = 8
=> -5 乙 + 9 丙 = 120...(4)

(3) + (4): 6 丙 = 240 => 丙 = 40 代入 (3)
5 乙 = 120 + 120 = 240
=> 乙 = 48 代回最前面的等式

甲 - 8 = 2/3 乙 = 32
=> 甲 = 40

甲 = 40, 乙 = 48, 丙 = 40

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