I wonder why this q be posted here...But this is not that difficult, all you need is to find out magnitude of each force along with the direction of the box moving. That is, dividing the forces to orthogonal ones, which are horizontal to the slope and vertical the other. Cross product may help but I think it's no neccessity.
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The work exerted on the box is the magnitude of the "horizontal" force times the moving distance 0.50 m