1
(1)
+
o
log, 10
1
log, 10
十
loglo
牛
2
(2) (log, 3) * (log3 4 +log, 2) •
luga
lug 5
解)
loglo
1
1
1
I
1
1
2
(1)
+
log, 10 log, 10 log 10
=log 2 + log 5=log 10=1 .
log 10
log 2 log 5
+
(2) (log23) (log34 +log, 2)=
log 3
log2
X
log 4
log 3
log2
+
log 9
log 3
log2
X
2 x log 2 log 2
+
log 3 2 x log 3
22
5 log2
X
2 3 2
5
O
- hoe2 ) love?
Julie
log 3
log2
X
Nlur,
基本上就是換底公式