✨ คำตอบที่ดีที่สุด ✨
想法一:當成直線,考慮斜率
OA 斜率為 1
OB 斜率為 -3/2
以差角公式計算 [ (-3/2) - 1 ]/[ 1 + (-3/2)·1 ]
= [ -5/2 ]/[ -1/2 ] = 5
想法二:找三角形關係
tan∠OAB = 1
tan∠OBA = 3/2
tan∠AOB = tan(180° - ∠OAB - ∠OBA)
= - tan(∠OAB + ∠OBA)
= - [ 1 + 3/2 ]/[ 1 - 1·(3/2) ]
= - [ 5/2 ]/[ -1/2 ]
= 5