Question

郁欣

求解，謝謝🙏

-x+y0-4:04x-4y+9=04x+3y-1
,此時數對
5. 若實數x,y滿足5x+12y=26,則x + y²的最小值為
-2
(x, y) =
4+9
√13
广

2. 坐標平面上,已知 (1,3),B(3,2),若直線L:2x-3y+k=0與 AB 線段有交點,
as - 8
則實數k的範圍為
MAB =
-2-3
3-1
Y-3 = 2/x - 520
5x+2y=1
zx-3y=k
A(1,3)
1

Answer 1

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