Question

Wn

求解這怎麼算呀😭

(x+1\<a
I 設a,b為正實數,已知聯立不等式.
的解為0<x<2,則數對(a,b)=
|2x-5<b
-a<x+1a
-a-+<x<α-1
-bLxx-5 <b -b+5 Lx <b+s
+o+5/><6+5
2