✨ ベストアンサー ✨
分段討論
(1) x > 2
2(x + 1) + (x - 2) - x - 8 = 0
2x + 2 + x - 2 - x - 8 = 0
2x = 8
x = 4 並確認有在一開始設定的範圍內
2. -1 < x < 2
2(x + 1) + (2 - x) - x - 8 = 0
2x + 2 - x + 2 - x - 8 = 0
無解
3. x < -1
2(-x - 1) + (2 - x) - x - 8 = 0
-2x - 2 - x + 2 - x - 8 = 0
4x = -8
x = -2 並確認有在一開始設定的範圍內