25
15.設0°<<90°,若tan +
sine
0059
5058
SUFF
tane 12
sin' A cose
,
求sin-cos0=
(sino-cose)"
L
Sine DOSE
= 1- > sino coso =====
sine cose => Sine 2058 =
5
16.設為銳角,已知sin 0:
13
,
試求tan-
=
17. (sin 60°)² + (tan 45°)² + (sin 30°)² +(cos 52° + cos 38°)² + (cos 52° - cos 38°)² =
=> 37 + 60
sin s
205450
+ sin 30° + cost 52° ± 60538°
+ +1 = 3
3
==
18.圓O為一單位圓,PQ切圓O於P點,BA與BC分別垂直於*軸、y軸,若PQ:
則矩形ABCO 的周長為
1,
1
19.已知 cos=tan0,0為銳角,求-
1
1-sin 1+sin
+
O AP
x