(b)
U=X X X = asu
dy dy du
√3x + 2x - 1) == dx = du dx
(Let U= 3x²+2x-1 & Y = √U = U²)
3
(tan
tan' (171))
(0) = (dam (1)
=U³² · (6x + 2) = = (3x + 2xX-1) ³ ((x+²) Q
dy_ dy dw dy = (3u²) (seciul) (2x)
1 -
dx
2
[let X=X+1, w=fonu, y=w²
UX
[x→u →W+Y]
= 3 tan(x²1)- sec ²(x+³1) (2x)