請問有人能幫忙解答這題嗎！！拜託各位微積分大神救救我qwq

Sis continuous at every positive real nurber Let cg > 0begiven. Let 5二 1 (20%) The following proofshows that 了(z) 二 Tet c > 0. We claimm that 了is continuous at e, 宮<A Then ~二 ve> Veand -Swpbpose Hence / is continuous at cc

求解第6題

人說站 Vyz+1 4A&+4|1 te 久(》 G)Suppose that 7/ is continuous and strictly increasing on [0,]] with /(0) 二0and /(1) =1and / /@ )它= Fmd 人 /1(9) 約 7 af 了7) 諸 A/1.L crna277 Ni人生店 人 中

求解！！！ 以H2O的三個原子的座標O(x1,y1,z1)、H1(x2,y2,z2)、H2(x3,y3z3)為bases，對所有classes產生出reducible representations（9*9矩陣部分）

第三題a b要怎麼證明?

(b) (10 pts) Prove thatlimza,j+ 0 = 2 ! 請 3. (20 pts) Prove that X?》 (a) 了() 一|2x避品 not continuous at X 三 0. (b) 了(福) 三 |2x和過誠 not differentiable at 文三 0. 4. (10 pts) The statement: “If xX > 0 andy > 說 歸 0thenx+于2 0. 和 光i生人 誤于

求解

50. Suppose that a function / is continuous on [0, 1] except at 0.25 and that /(0) 三 1and /(1) 三3.Let W 二2.Sketeh two Possible graphs of ./, one showing that 7 might not Satisfy the conclJusion of the Intermediate Value Theorem and one show- ng 了at / might Stil] satisfy the conclusion of the Intermediate Value Theorem (even though it doesnmt satisfy the hypothesis).

有誰會第40題嗎 請求幫忙

39-40 Show that 了is continuous on (一2, 9). 1三四 9. 7 三 到2 仍 和x>>1 sin議“主 < 三/4 中" 久 主 芳 也/4

求翻譯定理B和定理C 微積分

(see Problem 27 OfSCCU ous everyWheTe- By the Ma providedr point where continuous at each Teal nu 閣 akKeS SenSe to mberc 三 X/x 1] 1s COntInUuOUuS at . In particular, 外人) Root Functio 點s 開 teWery realnumber C. 五1s even, number C;註

第10題~求過程~

as 中華電信 4G 下午1:30 Homework 1.pdf 8. [10 points] 已知函數 _fqx?2十1 x<3 7 [條 ※寢3 連續,求a之值。 (Determine the value ofa Such that the function 1S continuous on number line.) 9. [10 points] 利用定義(求極限的方式)求導函數刻(x) : (Using the definition to solve 刻(x).) (3) 了) 三2 (b) /CG) 三VX 10. [10 points] 設/(Gz) =2-2G-9G-9-G-2 求/(0). (1+x)(2+x)(3+7x)...(9+x) xX(1~-x)(2~x)(3~-x)(9-) (1+x)(2+xX)(3+xX)一(9+X) (IT /(x) 三 solve 厂(0).)

求解3.79！！

點 Dofq for unilqferqgl cqses 點 Clear Antibiotic 0 1 Total ]| 24 38 02 外 39 2 66 Total 63 65 128 Dofoq for bilqfTerql cgqses 點 Clear Antibiotic 0 1 Total 3轉3 88 99 29 62 Total 70 02 0

求證此公式🙏

止 wedelilne eto beO when Ax 三 0, tthengebecomes acontinuous functlon of Ar. Thus, for a differentiable function we can Wwrlte 了 Ay 二了(2 0 Were 5 文人as Axz 人4 and eis acontinuous function of Ax. Thls property of differentlable tunctlons 1S what enables us to proye he Chain Rule.