應該是這樣吧...
第二行後面應該是: -27 +11 = 0
=> 3(x -3)^2 = 16
a = 3、b = -3、c = 16
哪泥 為什麼qwq
3x^2 -18x +11 = 0
3(x^2 -6x) +11 = 0
3(x -3)^2 +11 -3*(3^2) = 0
3(x -3)^2 +11 -27 = 0 (配方時多加了27,所以要扣掉27)
3(x -3)^2 = 27-11 = 16
=> a = 3、b = -3、c = 16
歐歐歐 我抄錯了
應該是這樣吧...
第二行後面應該是: -27 +11 = 0
=> 3(x -3)^2 = 16
a = 3、b = -3、c = 16
哪泥 為什麼qwq
3x^2 -18x +11 = 0
3(x^2 -6x) +11 = 0
3(x -3)^2 +11 -3*(3^2) = 0
3(x -3)^2 +11 -27 = 0 (配方時多加了27,所以要扣掉27)
3(x -3)^2 = 27-11 = 16
=> a = 3、b = -3、c = 16
歐歐歐 我抄錯了
看了這個問題的人
也有瀏覽這些問題喔😉
好的,謝謝