✨ 最佳解答 ✨ 綾 約1年以前 正比是相除為定值 即[3/(x+2y)] / [4/(2x+y)] = k 已知x = 4時y = 6 代入得k = [3/(4+12)] / [4/(8+6)] = 21/32 x = 6代入 [3/(6+2y)] / [4/(12+y)] = 21/32 => (36+3y) / (24+8y) = 21/32 => (12+y) / (3+y) = 7/4 => 48+4y = 21+7y => 3y = 27 => y = 9 青蛙🐸 約1年以前 謝謝🙏 留言
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